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Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H2 gas at the cathode is (1 Faraday = 96500 C mol-1)
  • a)
    9.65 x 104 sec
  • b)
    19.3 x 104 sec
  • c)
    28.95 x 104 sec
  • d)
    38.6 x 104 sec
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Electrolysis of dilute aqueous NaCl solution was carried out by passin...
According to Faraday's first law of electrolysis:
m = EIt/F
Where:
m = mass of substance
E = equivalent weight of substance
I = current in amperes
t = time required
F = 96,500 Coulombs
 
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Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H2 gas at the cathode is (1 Faraday = 96500 C mol-1)a)9.65 x 104secb)19.3 x 104secc)28.95 x 104secd)38.6 x 104secCorrect answer is option 'B'. Can you explain this answer?
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