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Electrolysis of dilute aqueous NaCI solution was carried out by passing 10 mA current. The time required to liberate 0.01 mole of H2 gas at the cathode is (1 F = 96500 C mol-1)
(2008,Only One Option Correct Type)
  • a)
    9.65 x 104 s
  • b)
    19.3 x 104 s
  • c)
    28.95 x 104 s
  • d)
    8.6 x 104 s
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Electrolysis of dilute aqueous NaCI solution was carried out by passin...
0.01 mol H2 = 0.02 g equivalent
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Electrolysis of dilute aqueous NaCI solution was carried out by passing 10 mA current. The time required to liberate 0.01 mole of H2 gas at the cathode is (1 F = 96500 C mol-1)(2008,Only One Option Correct Type)a)9.65 x 104sb)19.3x 104sc)28.95x 104sd)8.6x 104sCorrect answer is option 'B'. Can you explain this answer?
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Electrolysis of dilute aqueous NaCI solution was carried out by passing 10 mA current. The time required to liberate 0.01 mole of H2 gas at the cathode is (1 F = 96500 C mol-1)(2008,Only One Option Correct Type)a)9.65 x 104sb)19.3x 104sc)28.95x 104sd)8.6x 104sCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Electrolysis of dilute aqueous NaCI solution was carried out by passing 10 mA current. The time required to liberate 0.01 mole of H2 gas at the cathode is (1 F = 96500 C mol-1)(2008,Only One Option Correct Type)a)9.65 x 104sb)19.3x 104sc)28.95x 104sd)8.6x 104sCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Electrolysis of dilute aqueous NaCI solution was carried out by passing 10 mA current. The time required to liberate 0.01 mole of H2 gas at the cathode is (1 F = 96500 C mol-1)(2008,Only One Option Correct Type)a)9.65 x 104sb)19.3x 104sc)28.95x 104sd)8.6x 104sCorrect answer is option 'B'. Can you explain this answer?.
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