half the perimeter of rectangular garden whose length is 4m more than ...
Let width be x meter
Length = x + 4
Perimeter = 2 ( l + b )
Half of the perimeter = 36 m
2 ( x + 4) / 2 = 36
Both 2 cancel each other
x + 4 = 36
x = 36 - 4
x = 32
Width of rectangular garden = 32 m
Length of rectangular garden = 32 + 4 = 36 m
half the perimeter of rectangular garden whose length is 4m more than ...
Problem Statement: Find the dimensions of a rectangular garden whose length is 4m more than its width, and half the perimeter is 36m.
Given:
- Length of the rectangular garden = x + 4m
- Width of the rectangular garden = x
- Half the perimeter of the rectangular garden = 36m
To find: Dimensions of the rectangular garden
Solution:
Let's assume the width of the rectangular garden to be x.
Then the length of the rectangular garden would be (x+4) m.
Perimeter of a rectangle = 2 (length + width)
Half the perimeter of the rectangular garden = 36m
Therefore,
2 [(x+4) + x] / 2 = 36
2x + 4 = 72
2x = 68
x = 34
So, the width of the rectangular garden is 34m.
Length of the rectangular garden = x + 4 = 34 + 4 = 38m.
Thus, the dimensions of the rectangular garden are 34m x 38m.
Answer: The dimensions of the rectangular garden are 34m x 38m.