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A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the drawn ball is blue?
- a)10/21
- b)11/21
- c)9/21
- d)1/42
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at...
Possible out comes(E) or Favourable outcomes are
E1.2 red ball or
E2.2 green ball or
E3.1 red and 1 green
Number of selecting 2 balls from two red balls n(E)=2C2=1
Number of ways of selecting 2 balls from 3 green balls n(E2)= 3C2=3
Number of ways of selecting 1 red ball and 1 green ball n(E3)= 2C1*3C1=2*3=6
Sample space S=Number of ways of selecting 2 balls from 7(2+3+2) balls n(S)=7C2=21
n(E)=n(E1)+ n(E2)+ n(E3)=1+3+6=10
Required probability P(E)=n(E)/n(S)=10/21
Most Upvoted Answer
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at...
Solution:
Given, a bag contains 2 red, 3 green and 2 blue balls.
We need to find the probability that none of the drawn balls is blue.
Total number of balls = 2 + 3 + 2 = 7
Two balls can be drawn in 7C2 ways = 21 ways
Number of ways of drawing 2 balls such that none is blue = Number of ways of drawing 2 balls from 2 red and 3 green balls
= 5C2 = 10 ways
Probability of drawing 2 balls such that none is blue = 10/21
Therefore, the correct option is (a) 10/21.
Note:
- The total number of ways of drawing 2 balls can be found using the combination formula nCr where n is the total number of balls and r is the number of balls to be drawn.
- The number of ways of drawing 2 balls such that none is blue can be found by considering only the red and green balls, and using the combination formula again.
Given, a bag contains 2 red, 3 green and 2 blue balls.
We need to find the probability that none of the drawn balls is blue.
Total number of balls = 2 + 3 + 2 = 7
Two balls can be drawn in 7C2 ways = 21 ways
Number of ways of drawing 2 balls such that none is blue = Number of ways of drawing 2 balls from 2 red and 3 green balls
= 5C2 = 10 ways
Probability of drawing 2 balls such that none is blue = 10/21
Therefore, the correct option is (a) 10/21.
Note:
- The total number of ways of drawing 2 balls can be found using the combination formula nCr where n is the total number of balls and r is the number of balls to be drawn.
- The number of ways of drawing 2 balls such that none is blue can be found by considering only the red and green balls, and using the combination formula again.
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A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the drawn ball is blue?a)10/21b)11/21c)9/21d)1/42e)None of theseCorrect answer is option 'A'. Can you explain this answer? for Banking Exams 2025 is part of Banking Exams preparation. The Question and answers have been prepared according to the Banking Exams exam syllabus. Information about A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the drawn ball is blue?a)10/21b)11/21c)9/21d)1/42e)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Banking Exams 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the drawn ball is blue?a)10/21b)11/21c)9/21d)1/42e)None of theseCorrect answer is option 'A'. Can you explain this answer?.
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