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Two pipes can fill a cistern in 14 and 16 hours respectively. The pipes are opened simultaneously and found that due to leakage in bottom, extra 32 minutes are taken for filling the cistern. If the cistern is full, in what time leakage will empty it?
  • a)
    112hours
  • b)
    8hours
  • c)
    120hours
  • d)
    7hours
  • e)
    110hours
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two pipes can fill a cistern in 14 and 16 hours respectively. The pipe...
Work done by first pipe in 1 hr= 1/14
Work done by second pipe in 1 hr= 1/16
Work done by both pipes in 1 hr= 1/14 + 1/16 =15/112
Time taken by the pipes to fill the cistern(without leakage)= 112/15 = 7 hr 28 mts.
Actual time taken by the pipes to fill the cistern(including leakage)= 7 hr 28 mts+ 32 mts = 8 hrs.
 Work done by 2 pipes and leakage in 1 hr = 1/8
Work done by leak in 1 hr = 15/112 – 1/8 = 1/112
Time taken by the leak to empty cistern = 112 hrs
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Two pipes can fill a cistern in 14 and 16 hours respectively. The pipes are opened simultaneously and found that due to leakage in bottom, extra 32 minutes are taken for filling the cistern. If the cistern is full, in what time leakage will empty it?a)112hoursb)8hoursc)120hoursd)7hourse)110hoursCorrect answer is option 'A'. Can you explain this answer?
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