JEE Exam > JEE Questions > Two small balls carrying charges +9 micro C &...
Start Learning for Free
Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become.
? Related: Electric Charges Introduction
Verified Answer
Two small balls carrying charges +9 micro C & -4 micro C attract each ...
The force of attraction between two charged particles is given by Coulomb's Law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.
If two small balls carrying charges +9 micro C and -4 micro C attract each other with a force F, and we add a charge of -5 micro C to each one of them, the new charges will be +4 micro C and -9 micro C, respectively.
The force of attraction between the two balls with the new charges will be proportional to the product of the charges and inversely proportional to the square of the distance between them. This means that the new force will be different from the original force, but it is not possible to determine the exact value without knowing the distance between the balls.
This question is part of UPSC exam. View all JEE courses
Most Upvoted Answer
Two small balls carrying charges +9 micro C & -4 micro C attract each ...
And -3 micro C are placed 10 cm apart from each other. The force between them is given by Coulomb's law, which states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for Coulomb's law is:
F = k * (q1 * q2) / r^2
Where:
F = force between the charges
k = Coulomb's constant (9 x 10^9 Nm^2/C^2)
q1 and q2 = charges of the two balls
r = distance between the balls
Using this formula, we can calculate the force between the two balls:
F = (9 x 10^9 Nm^2/C^2) * (9 micro C * -3 micro C) / (0.1 m)^2
F = (9 x 10^9 Nm^2/C^2) * (-27 x 10^-12 C^2) / 0.01 m^2
F = -243 x 10^-3 N
Therefore, the force between the two balls is -243 millinewtons.
F = k * (q1 * q2) / r^2
Where:
F = force between the charges
k = Coulomb's constant (9 x 10^9 Nm^2/C^2)
q1 and q2 = charges of the two balls
r = distance between the balls
Using this formula, we can calculate the force between the two balls:
F = (9 x 10^9 Nm^2/C^2) * (9 micro C * -3 micro C) / (0.1 m)^2
F = (9 x 10^9 Nm^2/C^2) * (-27 x 10^-12 C^2) / 0.01 m^2
F = -243 x 10^-3 N
Therefore, the force between the two balls is -243 millinewtons.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction?
Question Description
Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction?.
Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction?.
Solutions for Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction? defined & explained in the simplest way possible. Besides giving the explanation of
Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction?, a detailed solution for Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction? has been provided alongside types of Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction? theory, EduRev gives you an
ample number of questions to practice Two small balls carrying charges +9 micro C & -4 micro C attract each other with a force F. If a charge of -5 micro C is added to each one of them, then the force become. Related: Electric Charges Introduction? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup