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A potential difference of 2V exists across a potentiometer wire of 2m length. When the potential difference across a 2Ω resistance of a second circuit is measured by this potentiometer wire, it amounts to 5mm balancing length. The current in the second circuit is
  • a)
    250A
  • b)
    25 x 10-4 A
  • c)
    1.5 A
  • d)
    2.5 A
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A potential difference of 2V exists across a potentiometer wire of 2m ...
2.5 mA
Potential gradient in the wire
= 2 2 = 1V/m
P.D. across a balancing length of 5 mm
= 5 x 10-3 x 1
= 5 x 10-3 V
∴ Current in the second circuit
= 5 x 10-3/2 = 2.5 x 10-3 A
= 25 x 10-4 A
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Most Upvoted Answer
A potential difference of 2V exists across a potentiometer wire of 2m ...
Given data:
Potential difference across potentiometer wire (V1) = 2V
Length of potentiometer wire (L) = 2m
Potential difference across 2Ω resistance (V2) = 5mm

Calculating the current:
- First, we need to calculate the total resistance of the potentiometer wire, which is given by:
Resistance (R) = V1 / I
R = 2 / I
- Using the formula for resistance of a wire:
R = ρ * L / A
Where ρ is the resistivity of the wire, L is the length, and A is the cross-sectional area.
- Since the resistivity and cross-sectional area are constant, we can write:
R1 / L1 = R2 / L2
R1 / 2 = R2 / 0.005
R2 = 0.01 * R1
- Substituting this back into the total resistance equation:
0.01 * R1 = 2 / I
I = 0.01 * 2 / R1
- Given that V2 = 2.5V and R2 = 2Ω, we can calculate R1:
R1 = V2 / I
2 = 2.5 / I
I = 2.5 / 2.5 x 10^-3
I = 25 x 10^-4 A
Therefore, the current in the second circuit is 25 x 10^-4 A.
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A potential difference of 2V exists across a potentiometer wire of 2m length. When the potential difference across a 2Ω resistance of a second circuit is measured by this potentiometer wire, it amounts to 5mm balancing length. The current in the second circuit isa)250Ab)25 x 10-4 Ac)1.5 Ad)2.5 ACorrect answer is option 'B'. Can you explain this answer?
Question Description
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