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A potential difference of 2V exists across a potentiometer wire of 2m length. When the potential difference across a 2Ω resistance of a second circuit is measured by this potentiometer wire, it amounts to 5mm balancing length. The current in the second circuit is
  • a)
    250A
  • b)
    25*10-4 A
  • c)
    1.5 A
  • d)
    2.5 A
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A potential difference of 2V exists across a potentiometer wire of 2m ...
2.5 mA
Potential gradient in the wire
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A potential difference of 2V exists across a potentiometer wire of 2m ...
Given Data:
- Potential difference across potentiometer wire = 2V
- Length of potentiometer wire = 2m
- Potential difference across a 2Ω resistance = 5mm balancing length

Calculations:
1. Calculate the total potential difference across the potentiometer wire:
- Given potential difference = 2V
- Length of potentiometer wire = 2m
- Potential difference per unit length = 2V/2m = 1V/m
2. Convert the balancing length to potential difference:
- Balancing length = 5mm = 0.005m
- Potential difference across 2Ω resistance = Potential difference per unit length * Balancing length
- Potential difference across 2Ω resistance = 1V/m * 0.005m = 0.005V
3. Calculate the current in the second circuit using Ohm's Law:
- Potential difference across 2Ω resistance = Current * Resistance
- 0.005V = Current * 2Ω
- Current = 0.005V / 2Ω = 0.0025A = 25*10^-4 A
Therefore, the current in the second circuit is 25*10^-4 A, which corresponds to option 'B'.
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A potential difference of 2V exists across a potentiometer wire of 2m length. When the potential difference across a 2Ω resistance of a second circuit is measured by this potentiometer wire, it amounts to 5mm balancing length. The current in the second circuit isa)250Ab)25*10-4 Ac)1.5 Ad)2.5 ACorrect answer is option 'B'. Can you explain this answer?
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