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A particle with a specific charge S is fired with a speed v towards a wall at a distance d, perpendicular to the wall. What minimum magnetic field must exist in this region for particle not hit the wall ?
- a)v/4sd
- b)v/2sd
- c)2v/sd
- d)v/sd
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A particle with a specific charge S is fired with a speed v towards a ...
The particle moves in a circular path with radius d if it is just to miss the wall
mv = Bqr
⇒ B = v ( q m ) d = v sd
mv = Bqr
⇒ B = v ( q m ) d = v sd
Most Upvoted Answer
A particle with a specific charge S is fired with a speed v towards a ...
To prevent the particle from hitting the wall, the magnetic force on the particle must provide the necessary centripetal force to keep it moving in a circular path.
Formula used:
The centripetal force on a charged particle moving in a circular path in a magnetic field B is given by:
F = Bqv
Where F is the force, B is the magnetic field, q is the charge on the particle, and v is the speed of the particle.
The centripetal force required to keep the particle moving in a circular path is given by:
F = mv^2 / r
Where m is the mass of the particle and r is the radius of the circular path.
Setting these two equations equal to each other and solving for B, we get:
B = mv / qr
Since the particle is fired perpendicular to the wall, the radius of the circular path it follows is equal to the distance d to the wall.
Substituting the given values, we get:
B = (mvd) / (qvd) = v / qd
Since the specific charge S is given by S = q/m, we can substitute q = Sm to get:
B = v / Sdm
Therefore, the minimum magnetic field required to prevent the particle from hitting the wall is given by:
B = v / Sdm
Option 'D' is correct.
Formula used:
The centripetal force on a charged particle moving in a circular path in a magnetic field B is given by:
F = Bqv
Where F is the force, B is the magnetic field, q is the charge on the particle, and v is the speed of the particle.
The centripetal force required to keep the particle moving in a circular path is given by:
F = mv^2 / r
Where m is the mass of the particle and r is the radius of the circular path.
Setting these two equations equal to each other and solving for B, we get:
B = mv / qr
Since the particle is fired perpendicular to the wall, the radius of the circular path it follows is equal to the distance d to the wall.
Substituting the given values, we get:
B = (mvd) / (qvd) = v / qd
Since the specific charge S is given by S = q/m, we can substitute q = Sm to get:
B = v / Sdm
Therefore, the minimum magnetic field required to prevent the particle from hitting the wall is given by:
B = v / Sdm
Option 'D' is correct.
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A particle with a specific charge S is fired with a speed v towards a wall at a distance d, perpendicular to the wall. What minimum magnetic field must exist in this region for particle not hit the wall ?a)v/4sdb)v/2sdc)2v/sdd)v/sdCorrect answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle with a specific charge S is fired with a speed v towards a wall at a distance d, perpendicular to the wall. What minimum magnetic field must exist in this region for particle not hit the wall ?a)v/4sdb)v/2sdc)2v/sdd)v/sdCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle with a specific charge S is fired with a speed v towards a wall at a distance d, perpendicular to the wall. What minimum magnetic field must exist in this region for particle not hit the wall ?a)v/4sdb)v/2sdc)2v/sdd)v/sdCorrect answer is option 'D'. Can you explain this answer?.
A particle with a specific charge S is fired with a speed v towards a wall at a distance d, perpendicular to the wall. What minimum magnetic field must exist in this region for particle not hit the wall ?a)v/4sdb)v/2sdc)2v/sdd)v/sdCorrect answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle with a specific charge S is fired with a speed v towards a wall at a distance d, perpendicular to the wall. What minimum magnetic field must exist in this region for particle not hit the wall ?a)v/4sdb)v/2sdc)2v/sdd)v/sdCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle with a specific charge S is fired with a speed v towards a wall at a distance d, perpendicular to the wall. What minimum magnetic field must exist in this region for particle not hit the wall ?a)v/4sdb)v/2sdc)2v/sdd)v/sdCorrect answer is option 'D'. Can you explain this answer?.
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