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The vapour pressure of pure water is 760mm at 25degree Celsius. The vapour pressure of solution containing 1 molal solution of glucose will be (1)761.0mm (2)746.5mm?
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The vapour pressure of pure water is 760mm at 25degree Celsius. The va...
Introduction
The vapour pressure of a solution is lower than that of the pure solvent. This is due to the presence of solute particles in the solution.
Determination of Vapour Pressure
The vapour pressure of a solution can be determined using Raoult's law which states that the vapour pressure of a solution is equal to the product of the mole fraction of the solvent and the vapour pressure of the pure solvent.
Calculation
Here, we have a 1 molal solution of glucose. This means that 1 mole of glucose is dissolved in 1000 g of water. The mole fraction of glucose in the solution is therefore:
Mole fraction of glucose = 1/ (1 + 18) = 0.0526
The mole fraction of water is:
Mole fraction of water = 18/ (1 + 18) = 0.9474
The vapour pressure of pure water at 25 degrees Celsius is 760 mmHg.
Therefore, using Raoult's law, the vapour pressure of the solution containing 1 molal solution of glucose will be:
Vapour pressure = Mole fraction of water x Vapour pressure of pure water
Vapour pressure = 0.9474 x 760 mmHg
Vapour pressure = 720.9 mmHg
Therefore, option (2) 746.5 mmHg is incorrect.
Conclusion
The correct answer is option (1) 761.0 mmHg.
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The vapour pressure of pure water is 760mm at 25degree Celsius. The vapour pressure of solution containing 1 molal solution of glucose will be (1)761.0mm (2)746.5mm?
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The vapour pressure of pure water is 760mm at 25degree Celsius. The vapour pressure of solution containing 1 molal solution of glucose will be (1)761.0mm (2)746.5mm? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The vapour pressure of pure water is 760mm at 25degree Celsius. The vapour pressure of solution containing 1 molal solution of glucose will be (1)761.0mm (2)746.5mm? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour pressure of pure water is 760mm at 25degree Celsius. The vapour pressure of solution containing 1 molal solution of glucose will be (1)761.0mm (2)746.5mm?.
The vapour pressure of pure water is 760mm at 25degree Celsius. The vapour pressure of solution containing 1 molal solution of glucose will be (1)761.0mm (2)746.5mm? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The vapour pressure of pure water is 760mm at 25degree Celsius. The vapour pressure of solution containing 1 molal solution of glucose will be (1)761.0mm (2)746.5mm? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour pressure of pure water is 760mm at 25degree Celsius. The vapour pressure of solution containing 1 molal solution of glucose will be (1)761.0mm (2)746.5mm?.
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