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0.1 (M) HCI and 0.1 (M) H2SO4 each of volume 2ml are mixed and the volume is made up to 6 ml by adding 2ml of 0.01 (N) NaCl solution. The pH of the resulting mixture is ​
  • a)
    1.17
  • b)
    1.0
  • c)
    0.3
  • d)
    log 2 – log 3
Correct answer is option 'B'. Can you explain this answer?
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0.1 (M) HCI and 0.1 (M) H2SO4 each of volume 2ml are mixed and the vol...
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0.1 (M) HCI and 0.1 (M) H2SO4 each of volume 2ml are mixed and the vol...
To find the pH of the resulting mixture, we need to calculate the concentration of H+ ions in the solution.

Step 1: Calculate the moles of H+ ions in HCI solution.
Moles of H+ ions in HCI solution = (0.1 M) * (2 ml / 1000 ml) = 0.0002 moles

Step 2: Calculate the moles of H+ ions in H2SO4 solution.
Moles of H+ ions in H2SO4 solution = (0.1 M) * (2 ml / 1000 ml) = 0.0002 moles

Step 3: Calculate the total moles of H+ ions in the mixture.
Total moles of H+ ions = Moles from HCI + Moles from H2SO4 = 0.0002 moles + 0.0002 moles = 0.0004 moles

Step 4: Calculate the concentration of H+ ions in the mixture.
Concentration of H+ ions = Total moles of H+ ions / Total volume of solution
Concentration of H+ ions = 0.0004 moles / 6 ml = 0.0004 moles / 0.006 L = 0.067 M

Step 5: Calculate the pOH of the mixture.
pOH = -log (concentration of OH- ions)
Since the solution is acidic, we can assume that all OH- ions react with H+ ions to form water, so the concentration of OH- ions is negligible.

Step 6: Calculate the pH of the mixture.
pH = 14 - pOH = 14 - (-log (0.067)) = 14 - (-1.18) = 14 + 1.18 = 15.18

Therefore, the pH of the resulting mixture is not one of the options provided.
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