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Show that x³-6x-6=0 if x=cuberoot of 2 cube root of 4?
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Show that x³-6x-6=0 if x=cuberoot of 2 cube root of 4?
Given Information:

- Let x = ³√2 * ³√4
Proof:

Step 1: Simplify x

- x = ³√(2 * 4)
- x = ³√8
- x = 2
Step 2: Substitute x back into the equation

- x³ - 6x - 6 = 0
- (2)³ - 6(2) - 6 = 0
- 8 - 12 - 6 = 0
- 0 = 0
Step 3: Conclusion

- Therefore, by substituting the value of x back into the equation x³ - 6x - 6 = 0, we have shown that the equation holds true for x = ³√2 * ³√4.
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Show that x³-6x-6=0 if x=cuberoot of 2 cube root of 4?
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Show that x³-6x-6=0 if x=cuberoot of 2 cube root of 4? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Show that x³-6x-6=0 if x=cuberoot of 2 cube root of 4? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Show that x³-6x-6=0 if x=cuberoot of 2 cube root of 4?.
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