JEE Exam > JEE Questions > By a cell a current of 0.9 A flows through 2 ...
Start Learning for Free
By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]
- a)0.5Ω
- b)1.0Ω
- c)1.2Ω
- d)2.0Ω
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A th...
In Istcas E-V*R+r=i.
E-V*2+r=.9
in 2nd case
E-V*7+r=0.3
on solving both equation
you will get ans.0.5A
E-V*2+r=.9
in 2nd case
E-V*7+r=0.3
on solving both equation
you will get ans.0.5A
Free Test
FREE
| Start Free Test |
Community Answer
By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A th...
To find the internal resistance of the cell, we can use Ohm's Law and Kirchhoff's Laws.
Let's assume that the internal resistance of the cell is R.
According to Ohm's Law, the voltage across a resistor is equal to the current through it multiplied by its resistance.
For the 2 ohm resistor, the voltage is V1 = 0.9 A * 2 ohm = 1.8 V.
For the 7 ohm resistor, the voltage is V2 = 0.3 A * 7 ohm = 2.1 V.
According to Kirchhoff's Law, the total voltage across the resistors in series is equal to the sum of the individual voltages.
So, V1 + V2 = E, where E is the voltage of the cell.
1.8 V + 2.1 V = E
3.9 V = E
According to Ohm's Law, the voltage of the cell is E = I * (R + r), where I is the total current and r is the internal resistance.
Substituting the given values:
3.9 V = (0.9 A + 0.3 A) * (2 ohm + R)
3.9 V = 1.2 A * (2 ohm + R)
3.9 V = 2.4 ohm + 1.2 A * R
1.5 V = 1.2 A * R
R = 1.5 V / 1.2 A
R = 1.25 ohm
Therefore, the internal resistance of the cell is approximately 1.25 ohm.
Let's assume that the internal resistance of the cell is R.
According to Ohm's Law, the voltage across a resistor is equal to the current through it multiplied by its resistance.
For the 2 ohm resistor, the voltage is V1 = 0.9 A * 2 ohm = 1.8 V.
For the 7 ohm resistor, the voltage is V2 = 0.3 A * 7 ohm = 2.1 V.
According to Kirchhoff's Law, the total voltage across the resistors in series is equal to the sum of the individual voltages.
So, V1 + V2 = E, where E is the voltage of the cell.
1.8 V + 2.1 V = E
3.9 V = E
According to Ohm's Law, the voltage of the cell is E = I * (R + r), where I is the total current and r is the internal resistance.
Substituting the given values:
3.9 V = (0.9 A + 0.3 A) * (2 ohm + R)
3.9 V = 1.2 A * (2 ohm + R)
3.9 V = 2.4 ohm + 1.2 A * R
1.5 V = 1.2 A * R
R = 1.5 V / 1.2 A
R = 1.25 ohm
Therefore, the internal resistance of the cell is approximately 1.25 ohm.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer?
Question Description
By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer?.
By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer?.
Solutions for By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is [KCET 2003]a)0.5Ωb)1.0Ωc)1.2Ωd)2.0ΩCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup