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ACT Exam  >  ACT Questions  >  An optically active hydrocarbon X has molecul... Start Learning for Free
An optically active hydrocarbon X has molecular formula C6H12. X on catalytic hydrogenation gives optically inactive C6H14. X could be
  • a)
    3-methyl-1-pentene
  • b)
    3-methyl-2-pentene
  • c)
    4-methyl-2-pentene
  • d)
    2-ethyl-1 -butene
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
An optically active hydrocarbon X has molecular formula C6H12. X on ca...
The optically active C6H1 2 hydrocarbon is 3-Methylpent-1-ene, having one chiral carbon shown in fig A.
On catalytic hydrogenation , the compound obtained is shown in fig B, and the molecule does not have chiral carbon.
The reaction is C6H1 2 → C6H1 4 and this reaction takes place inthe presence of H2 and Pd.
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Most Upvoted Answer
An optically active hydrocarbon X has molecular formula C6H12. X on ca...
Optically Active Hydrocarbon X

Molecular Formula: C6H12

Reaction: Catalytic Hydrogenation of X gives C6H14 (optically inactive)

Possible Structures:
a) 3-methyl-1-pentene
b) 3-methyl-2-pentene
c) 4-methyl-2-pentene
d) 2-ethyl-1-butene

Explanation:

1. Determining the Chiral Center:
To determine the optically active hydrocarbon X, we need to identify its chiral center. A chiral center is a carbon atom that is bonded to four different groups. In the given molecular formula C6H12, there are multiple possibilities for chiral centers.

2. Analyzing the Isomers:
a) 3-methyl-1-pentene:
In this isomer, the carbon atom attached to the methyl group is bonded to two different alkyl groups (ethyl and butyl). Therefore, it can be a potential chiral center.

b) 3-methyl-2-pentene:
In this isomer, the carbon atom attached to the methyl group is bonded to two ethyl groups. This carbon atom cannot be a chiral center as it is bonded to two identical groups.

c) 4-methyl-2-pentene:
In this isomer, the carbon atom attached to the methyl group is bonded to two ethyl groups. This carbon atom cannot be a chiral center as it is bonded to two identical groups.

d) 2-ethyl-1-butene:
In this isomer, the carbon atom attached to the ethyl group is bonded to two different alkyl groups (methyl and butyl). Therefore, it can be a potential chiral center.

3. Chiral Carbon in 3-methyl-1-pentene:
The isomer 3-methyl-1-pentene has a chiral carbon atom as discussed earlier. Since the catalytic hydrogenation of X gives an optically inactive compound, it indicates the presence of a chiral center in X. Therefore, the correct answer is option 'A' - 3-methyl-1-pentene.

Conclusion:
The optically active hydrocarbon X with the molecular formula C6H12 can be identified as 3-methyl-1-pentene. The presence of a chiral center in this compound leads to its optical activity.
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An optically active hydrocarbon X has molecular formula C6H12. X on ca...
Compound F has the molecular formula C5H8 and is optically active. On catalytic hydrogenation F yeilds G(C5H12) is optically inactive. Propose structures for F and G.
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An optically active hydrocarbon X has molecular formula C6H12. X on catalytic hydrogenation gives optically inactive C6H14. X could bea)3-methyl-1-penteneb)3-methyl-2-pentenec)4-methyl-2-pentened)2-ethyl-1 -buteneCorrect answer is option 'A'. Can you explain this answer?
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An optically active hydrocarbon X has molecular formula C6H12. X on catalytic hydrogenation gives optically inactive C6H14. X could bea)3-methyl-1-penteneb)3-methyl-2-pentenec)4-methyl-2-pentened)2-ethyl-1 -buteneCorrect answer is option 'A'. Can you explain this answer? for ACT 2025 is part of ACT preparation. The Question and answers have been prepared according to the ACT exam syllabus. Information about An optically active hydrocarbon X has molecular formula C6H12. X on catalytic hydrogenation gives optically inactive C6H14. X could bea)3-methyl-1-penteneb)3-methyl-2-pentenec)4-methyl-2-pentened)2-ethyl-1 -buteneCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for ACT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An optically active hydrocarbon X has molecular formula C6H12. X on catalytic hydrogenation gives optically inactive C6H14. X could bea)3-methyl-1-penteneb)3-methyl-2-pentenec)4-methyl-2-pentened)2-ethyl-1 -buteneCorrect answer is option 'A'. Can you explain this answer?.
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