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. If npr = 336 and nCr = 56, then n and r will be (a) (3, 2) (b) (8, 3) (c) (7, 4) (d) none of these?
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. If npr = 336 and nCr = 56, then n and r will be (a) (3, 2) (b) (8, 3...
Solution:

Given, nPr = 336 and nCr = 56.

We know that nCr = nPr / r!

Therefore, nPr = nCr × r!

336 = 56 × r!

r! = 6

On solving this equation, we get r = 3.

Now, we can substitute the value of r in any of the given equations to find the value of n.

nCr = nPr / r!

56 = nPr / 3!

nPr = 56 × 3! = 336

On comparing this with the given value of nPr, we get n = 8.

Therefore, the correct option is (b) (8, 3).

Hence, we can conclude that if nPr = 336 and nCr = 56, then n and r will be (8, 3).
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. If npr = 336 and nCr = 56, then n and r will be (a) (3, 2) (b) (8, 3...
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. If npr = 336 and nCr = 56, then n and r will be (a) (3, 2) (b) (8, 3) (c) (7, 4) (d) none of these?
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. If npr = 336 and nCr = 56, then n and r will be (a) (3, 2) (b) (8, 3) (c) (7, 4) (d) none of these? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about . If npr = 336 and nCr = 56, then n and r will be (a) (3, 2) (b) (8, 3) (c) (7, 4) (d) none of these? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for . If npr = 336 and nCr = 56, then n and r will be (a) (3, 2) (b) (8, 3) (c) (7, 4) (d) none of these?.
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