To solve this problem, we need to use the formulas for permutations (nPr) and combinations (nCr) and then find the values of n and r that satisfy the given conditions.

**Formulas:**
- Permutations: nPr = n! / (n - r)!
- Combinations: nCr = n! / (r! * (n - r)!)

Given:
- nPr = 336
- nCr = 56

**Step 1: Find the value of nPr = 336**
Let's find the value of nPr using the given information.

nPr = 336

Using the formula for permutations, we have:

336 = n! / (n - r)!

We can rewrite this equation as:

n! = 336 * (n - r)!

**Step 2: Find the value of nCr = 56**
Now, let's find the value of nCr using the given information.

nCr = 56

Using the formula for combinations, we have:

56 = n! / (r! * (n - r)!)

We can rewrite this equation as:

n! = 56 * r! * (n - r)!

**Step 3: Equate the values of n! obtained from Step 1 and Step 2**
Since both nPr and nCr are equal to n!, we can equate the values obtained from Step 1 and Step 2.

336 * (n - r)! = 56 * r! * (n - r)!

We can cancel out (n - r)! from both sides of the equation.

336 = 56 * r!

Divide both sides by 56 to solve for r!.

6 = r!

So, r = 3.

**Step 4: Substitute the value of r into the equations**
Now, let's substitute the value of r into the equations obtained from Step 1 and Step 2.

From Step 1:
n! = 336 * (n - 3)!

From Step 2:
n! = 56 * 3! * (n - 3)!

Since both equations represent the same value of n!, we can equate them.

336 * (n - 3)! = 56 * 3! * (n - 3)!

336 = 56 * 3

336 = 168

This is not possible, so our assumption that nPr = 336 and nCr = 56 is incorrect.

Therefore, none of the given options (A), (B), (C) are correct.

The correct answer is option (D) - none of these.

Note: The given values of nPr = 336 and nCr = 56 do not have a solution that satisfies both conditions.