A galvanoeteis tested in the circuit where E=1.5 V,R1=1.0 ohm R2 = 250...
Calculation of Galvanometer Resistance
Given Parameters:
- E = 1.5 V
- R1 = 1.0 ohm
- R2 = 2500 ohm
- R3 = 45 ohm (for 140 mm deflection)
- R3 = 950 ohm (for 70 mm deflection)
Calculation:
Galvanometer is a sensitive instrument used to measure small electric currents. It is always connected in series with a high resistance to limit the current passing through it. In this problem, we have to calculate the resistance of the galvanometer.
The circuit diagram is as follows:
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From the circuit diagram, we can write the equation for the current passing through the galvanometer as:
I = (E/R1) - (E/R2) - (E/R3)
When R3 = 45 ohm, the galvanometer deflection is 140 mm. This means the current passing through the galvanometer is:
I1 = K1 * 140 mm
where K1 is the galvanometer constant.
Similarly, when R3 = 950 ohm, the galvanometer deflection is 70 mm. This means the current passing through the galvanometer is:
I2 = K2 * 70 mm
where K2 is the galvanometer constant.
Since the galvanometer resistance is high, we can assume that the current passing through it is very small. Therefore, we can neglect the current passing through R1 and R2.
Equating the two expressions for the current passing through the galvanometer, we get:
(E/R3) = K1 * (140 mm) = K2 * (70 mm)
Therefore, we can write:
K1/K2 = 2
Since the galvanometer resistance is high, its current carrying capacity is very low. Therefore, we can assume that the current passing through it is negligible and it acts as an open circuit. This means that the potential difference across the galvanometer is zero.
Therefore, we can write:
(E/Rg) = (E/R3)
where Rg is the resistance of the galvanometer.
Substituting the value of R3 from the first equation, we get:
Rg = (140/950) * 2500 = 368.42 ohm
Answer:
The resistance of the galvanometer is 368.42 ohm.