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Equal charges are given to two conducting spheres of different radii. The potential will
  • a)
    be more on the smaller sphere
  • b)
    be more on the bigger sphere
  • c)
    be equal on both the sphere
  • d)
    depends on the nature of the materials of the sphere
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Equal charges are given to two conducting spheres of different radii. ...
Explanation:
When equal charges are given to two conducting spheres of different radii, the potential will be more on the smaller sphere. This can be explained using the following points:

- The potential of a conductor depends on its radius and the amount of charge it carries. The potential is directly proportional to the charge and inversely proportional to the radius.
- The smaller sphere has a smaller radius than the bigger sphere, so it will have a higher potential for the same amount of charge.
- This can be mathematically expressed using the formula for potential, which is V = kQ/r, where V is the potential, Q is the charge, r is the radius, and k is a constant.
- Since the charge is the same for both spheres, the potential will depend only on the radius. The smaller sphere will have a higher potential because its radius is smaller.
- Therefore, option A is the correct answer.

In summary, the potential of a conducting sphere depends on its radius and the amount of charge it carries. When equal charges are given to two conducting spheres of different radii, the potential will be more on the smaller sphere due to its smaller radius.
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Community Answer
Equal charges are given to two conducting spheres of different radii. ...
Explanation:
When equal charges are given to two conducting spheres of different radii, the potential will be more on the smaller sphere. This is because the potential is directly proportional to the ratio of the charge and the radius of the sphere.

- The potential of a sphere is given by the equation V = Q/4πεr, where V is potential, Q is the charge on the sphere, ε is the permittivity of free space and r is the radius of the sphere.
- If we assume that the charges on both spheres are the same, then the potential of the smaller sphere will be greater because its radius is smaller. This means that the same amount of charge is concentrated on a smaller surface area, resulting in a higher potential.
- On the other hand, the potential of the larger sphere will be less because its radius is larger. This means that the same amount of charge is spread over a larger surface area, resulting in a lower potential.
- Therefore, the potential on the smaller sphere will be more than that on the larger sphere.

Conclusion:
Hence, we can conclude that when equal charges are given to two conducting spheres of different radii, the potential will be more on the smaller sphere.
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