?The conductivity of 0.01 M NaCl solution is 0.00147 per ohm pet cm. W...
Effect of adding H2O to a 0.01 M NaCl solution on its conductivity
Given:
- Concentration of NaCl solution = 0.01 M
- Conductivity of NaCl solution = 0.00147 per ohm per cm
- Volume of NaCl solution = 100 ml
- Volume of H2O added = 100 ml
Calculating the new concentration
The addition of 100 ml of H2O to the 100 ml of 0.01 M NaCl solution results in a dilution of the solution. The new volume of the solution is 200 ml. Therefore, the new concentration of the solution can be calculated as follows:
New concentration = (Original concentration x Original volume) / New volume
New concentration = (0.01 M x 100 ml) / 200 ml
New concentration = 0.005 M
Calculating the new conductivity
The conductivity of a solution is directly proportional to the concentration of ions in the solution. Hence, the addition of H2O to the NaCl solution will result in a decrease in the concentration of ions in the solution, leading to a decrease in conductivity. The new conductivity can be calculated using the following formula:
New conductivity = Original conductivity x (New concentration / Original concentration)
New conductivity = 0.00147 per ohm per cm x (0.005 M / 0.01 M)
New conductivity = 0.000735 per ohm per cm
Conclusion
The conductivity of the 0.01 M NaCl solution decreases from 0.00147 per ohm per cm to 0.000735 per ohm per cm on the addition of 100 ml of H2O.