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The resistance of a conductivity cell filled with 0.01N solution of NaCl is 210 ohm a t 1 8 o C . Calculate the equivalent conductivity of the solution. The cell constant of the conductivity cell is 0.88 cm−1?
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Calculation of Equivalent Conductivity of 0.01N NaCl Solution
Given:
- Resistance of conductivity cell (R) = 210 ohm
- Concentration of NaCl solution (C) = 0.01 N
- Cell constant (l) = 0.88 cm⁻¹
- Temperature (T) = 18°C
Formula:
Equivalent Conductivity (Λ) = K × R
where K = l/C
Solution:
1. Calculation of K
K = l/C
K = 0.88 cm⁻¹ / 0.01 N
K = 88 cm² eq⁻¹
2. Calculation of Λ
Λ = K × R
Λ = 88 cm² eq⁻¹ × 210 ohm
Λ = 18480 cm² eq⁻¹
Answer:
The equivalent conductivity of the 0.01N NaCl solution is 18480 cm² eq⁻¹ at 18°C.
Given:
- Resistance of conductivity cell (R) = 210 ohm
- Concentration of NaCl solution (C) = 0.01 N
- Cell constant (l) = 0.88 cm⁻¹
- Temperature (T) = 18°C
Formula:
Equivalent Conductivity (Λ) = K × R
where K = l/C
Solution:
1. Calculation of K
K = l/C
K = 0.88 cm⁻¹ / 0.01 N
K = 88 cm² eq⁻¹
2. Calculation of Λ
Λ = K × R
Λ = 88 cm² eq⁻¹ × 210 ohm
Λ = 18480 cm² eq⁻¹
Answer:
The equivalent conductivity of the 0.01N NaCl solution is 18480 cm² eq⁻¹ at 18°C.
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The resistance of a conductivity cell filled with 0.01N solution of NaCl is 210 ohm a t 1 8 o C . Calculate the equivalent conductivity of the solution. The cell constant of the conductivity cell is 0.88 cm−1?
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The resistance of a conductivity cell filled with 0.01N solution of NaCl is 210 ohm a t 1 8 o C . Calculate the equivalent conductivity of the solution. The cell constant of the conductivity cell is 0.88 cm−1? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The resistance of a conductivity cell filled with 0.01N solution of NaCl is 210 ohm a t 1 8 o C . Calculate the equivalent conductivity of the solution. The cell constant of the conductivity cell is 0.88 cm−1? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The resistance of a conductivity cell filled with 0.01N solution of NaCl is 210 ohm a t 1 8 o C . Calculate the equivalent conductivity of the solution. The cell constant of the conductivity cell is 0.88 cm−1?.
The resistance of a conductivity cell filled with 0.01N solution of NaCl is 210 ohm a t 1 8 o C . Calculate the equivalent conductivity of the solution. The cell constant of the conductivity cell is 0.88 cm−1? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The resistance of a conductivity cell filled with 0.01N solution of NaCl is 210 ohm a t 1 8 o C . Calculate the equivalent conductivity of the solution. The cell constant of the conductivity cell is 0.88 cm−1? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The resistance of a conductivity cell filled with 0.01N solution of NaCl is 210 ohm a t 1 8 o C . Calculate the equivalent conductivity of the solution. The cell constant of the conductivity cell is 0.88 cm−1?.
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