This section contains 4 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its answer, out which ONE OR MORE is/are correct. Select the correct statement(s) about the above compounds from the following:a),Compounds (I) and (III) will reduce Fehlings solution and will also mutarotateb),Compound (IV) will reduce Tollens reagent but not mutarotatec)Compound (II) will not be reducing but mutarotatingd)The product(s) of the acid catalysed hydrolysis of both (II) and (III) will be reducing but not mutarotatingCorrect answer is option 'A,B'. Can you explain this answer?

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This section contains 4 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its answer, out which ONE OR MORE is/are correct.

Select the correct statement(s) about the above compounds from the following:

a)
,Compounds (I) and (III) will reduce Fehling’s solution and will also mutarotate
b)
,Compound (IV) will reduce Tollen’s reagent but not mutarotate
c)
Compound (II) will not be reducing but mutarotating
d)
The product(s) of the acid catalysed hydrolysis of both (II) and (III) will be reducing but not mutarotating

Correct answer is option 'A,B'. Can you explain this answer?

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This section contains 4 multiple choice questions. Each question has 4...

All reducing sugars are muatrotating. Although (IV) is an α - hydroxy ketone and hence reducing but it can’t mutarotate as it not a carbohydrate, can’t form ring. In (II) the glycosidic linkage is in between two anomeric carbons and hence ring opening can’t occur, thus non – reducing as well as non – mutarotating.

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Consider a solution of CH3COONH4 which is a salt of weak acid weak base. Theequilibrium involved in the solutions are :If we add these three reactions, then the net reaction isBoth CH3C00- and NH4 get hydrolysed independently and their hydrolysis depends on(i) their initial concentration(ii) the value of Kh which is Since both of the ions were produced from the same salt, their initial concentrations are same . Therefore unless untial the value of Kw/Kaand Kb is same, the degree of hydrolysis of ion cant be same.To explain why we assume that degree of hydrolysis of cation and anion is same, we need to now look at the third reaction i.e., combination of H+ and OH ions. It is obvious that this reaction happens only because one reaction produced H+ ion and the other produced OH ions. We can also note that this reaction causes both the hydrolysis reaction to occur more since their product ions are being consumed. Keep this thing in mind that the equilibrium which has smaller value of equilibrium conxtant is affected more by the common ion effect. For the same reason if for any reason a reaction is made to occur to a greater extent by the consumption of any one of the product ion, the reaction with the smaller value of equilibrium constant tends to get affected more.Therefore we conclude that firstly the hydrolysis of both the ions ocurs more in the presence of each other (due to consumption of the product ions) than in each other is absence. Secondly the hydrolysis of the ion which occurs to a lesser extent (due to smaller value of Kh) is affected more than the one whose Kh is greater. Hence we can see that the degree of hydrolysis of both the ions would be close to each other when they are getting hydrolysed in the presence of each other.Q.In a solution of NaHCO3 , the amphiprotic anion can under ionization to form H+ ion and hydrolysis to from OH ion.To calculat PH, suitable approximation is

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This section contains 4 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its answer, out which ONE OR MORE is/are correct. Select the correct statement(s) about the above compounds from the following:a),Compounds (I) and (III) will reduce Fehlings solution and will also mutarotateb),Compound (IV) will reduce Tollens reagent but not mutarotatec)Compound (II) will not be reducing but mutarotatingd)The product(s) of the acid catalysed hydrolysis of both (II) and (III) will be reducing but not mutarotatingCorrect answer is option 'A,B'. Can you explain this answer?

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