Area of a circle inscribed in a square is 308 cm2.The length of the di...
Let's assume that the side length of the square is "s".
Since the circle is inscribed in the square, its diameter must be equal to the side length of the square. Therefore, the diameter of the circle is also "s".
The area of a circle is given by the formula A = πr^2, where "r" is the radius of the circle. Since the diameter is equal to the side length of the square, we can say that the radius of the circle is equal to half the side length of the square, which is s/2.
So, the area of the circle is A = π(s/2)^2 = πs^2/4.
We are given that the area of the circle is 308 cm^2, so we can set up the equation:
πs^2/4 = 308.
To find the length of the diagonal of the square, we need to find the length of one side of the square first. We can solve the equation above for s:
πs^2 = 308 * 4.
s^2 = (308 * 4)/π.
s = sqrt((308 * 4)/π).
The length of the diagonal of the square is equal to s * sqrt(2). So, the length of the diagonal is:
sqrt((308 * 4)/π) * sqrt(2).
Simplifying this expression, we get:
sqrt((308 * 4 * 2)/π).
Calculating this expression, we find that the length of the diagonal of the square is approximately 27.94 cm.