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P, Q are two points on the rectangular hyperbola (x – 1)(y – 2) = c2, O is the centre of hyperbola, also tangent at P is perpendicular to OQ and meets OQ at N such that (OQ)(ON)=4 
Q.
An ellipse confocal with the hyperbola and with eccentricity equal to  is intersected by the line x + y – 7 = 0 at A and B, then intersection point of tangents at A and B will lie on
  • a)
    x + y – 8 = 0 
  • b)
     x + y – 9 = 0 
  • c)
    x + y – 11 = 0
  • d)
    x + y – 13 = 0
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
P, Q are two points on the rectangular hyperbola (x 1)(y 2) = c2, O ...

so equation of hyperbola is (x – 1)(y – 2) = 2  
Its foci are (−1, 0), (3, 4) and equation of directrix is x + y – 5 = 0, x + y – 7 = 0 is the equation of latus rectum of ellipse and tangents at end points of latus rectum always intersects on corresponding directrix.   
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P, Q are two points on the rectangular hyperbola (x 1)(y 2) = c2, O is the centre of hyperbola, also tangent at P is perpendicular to OQ and meets OQ at N such that (OQ)(ON)=4Q.An ellipse confocal with the hyperbola and with eccentricity equal to is intersected bythe line x + y 7 = 0 at A and B, then intersection point of tangents at A and B will lie ona)x + y 8 = 0b)x + y 9 = 0c)x + y 11 = 0d)x + y 13 = 0Correct answer is option 'C'. Can you explain this answer?
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P, Q are two points on the rectangular hyperbola (x 1)(y 2) = c2, O is the centre of hyperbola, also tangent at P is perpendicular to OQ and meets OQ at N such that (OQ)(ON)=4Q.An ellipse confocal with the hyperbola and with eccentricity equal to is intersected bythe line x + y 7 = 0 at A and B, then intersection point of tangents at A and B will lie ona)x + y 8 = 0b)x + y 9 = 0c)x + y 11 = 0d)x + y 13 = 0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about P, Q are two points on the rectangular hyperbola (x 1)(y 2) = c2, O is the centre of hyperbola, also tangent at P is perpendicular to OQ and meets OQ at N such that (OQ)(ON)=4Q.An ellipse confocal with the hyperbola and with eccentricity equal to is intersected bythe line x + y 7 = 0 at A and B, then intersection point of tangents at A and B will lie ona)x + y 8 = 0b)x + y 9 = 0c)x + y 11 = 0d)x + y 13 = 0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for P, Q are two points on the rectangular hyperbola (x 1)(y 2) = c2, O is the centre of hyperbola, also tangent at P is perpendicular to OQ and meets OQ at N such that (OQ)(ON)=4Q.An ellipse confocal with the hyperbola and with eccentricity equal to is intersected bythe line x + y 7 = 0 at A and B, then intersection point of tangents at A and B will lie ona)x + y 8 = 0b)x + y 9 = 0c)x + y 11 = 0d)x + y 13 = 0Correct answer is option 'C'. Can you explain this answer?.
Solutions for P, Q are two points on the rectangular hyperbola (x 1)(y 2) = c2, O is the centre of hyperbola, also tangent at P is perpendicular to OQ and meets OQ at N such that (OQ)(ON)=4Q.An ellipse confocal with the hyperbola and with eccentricity equal to is intersected bythe line x + y 7 = 0 at A and B, then intersection point of tangents at A and B will lie ona)x + y 8 = 0b)x + y 9 = 0c)x + y 11 = 0d)x + y 13 = 0Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of P, Q are two points on the rectangular hyperbola (x 1)(y 2) = c2, O is the centre of hyperbola, also tangent at P is perpendicular to OQ and meets OQ at N such that (OQ)(ON)=4Q.An ellipse confocal with the hyperbola and with eccentricity equal to is intersected bythe line x + y 7 = 0 at A and B, then intersection point of tangents at A and B will lie ona)x + y 8 = 0b)x + y 9 = 0c)x + y 11 = 0d)x + y 13 = 0Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of P, Q are two points on the rectangular hyperbola (x 1)(y 2) = c2, O is the centre of hyperbola, also tangent at P is perpendicular to OQ and meets OQ at N such that (OQ)(ON)=4Q.An ellipse confocal with the hyperbola and with eccentricity equal to is intersected bythe line x + y 7 = 0 at A and B, then intersection point of tangents at A and B will lie ona)x + y 8 = 0b)x + y 9 = 0c)x + y 11 = 0d)x + y 13 = 0Correct answer is option 'C'. Can you explain this answer?, a detailed solution for P, Q are two points on the rectangular hyperbola (x 1)(y 2) = c2, O is the centre of hyperbola, also tangent at P is perpendicular to OQ and meets OQ at N such that (OQ)(ON)=4Q.An ellipse confocal with the hyperbola and with eccentricity equal to is intersected bythe line x + y 7 = 0 at A and B, then intersection point of tangents at A and B will lie ona)x + y 8 = 0b)x + y 9 = 0c)x + y 11 = 0d)x + y 13 = 0Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of P, Q are two points on the rectangular hyperbola (x 1)(y 2) = c2, O is the centre of hyperbola, also tangent at P is perpendicular to OQ and meets OQ at N such that (OQ)(ON)=4Q.An ellipse confocal with the hyperbola and with eccentricity equal to is intersected bythe line x + y 7 = 0 at A and B, then intersection point of tangents at A and B will lie ona)x + y 8 = 0b)x + y 9 = 0c)x + y 11 = 0d)x + y 13 = 0Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice P, Q are two points on the rectangular hyperbola (x 1)(y 2) = c2, O is the centre of hyperbola, also tangent at P is perpendicular to OQ and meets OQ at N such that (OQ)(ON)=4Q.An ellipse confocal with the hyperbola and with eccentricity equal to is intersected bythe line x + y 7 = 0 at A and B, then intersection point of tangents at A and B will lie ona)x + y 8 = 0b)x + y 9 = 0c)x + y 11 = 0d)x + y 13 = 0Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
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