In your office 4 posts have fallen vacant. In how many ways a selectio...
Solution:
We can solve this problem using the combination formula.
a) If one candidate is always included, then we need to select 3 candidates out of 30 remaining candidates.
The number of ways to select 3 candidates out of 30 candidates is 30C3.
b) If one candidate is always excluded, then we need to select 4 candidates out of 30 remaining candidates.
The number of ways to select 4 candidates out of 30 candidates is 30C4.
Therefore, the answer is option B.
Explanation:
To solve this problem, we need to use the combination formula which is given by:
nCr = n! / (r! * (n-r)!)
where n is the total number of candidates, r is the number of candidates to be selected, and nCr is the number of ways to select r candidates out of n candidates.
a) If one candidate is always included, then we need to select 3 candidates out of 30 remaining candidates.
The number of ways to select 3 candidates out of 30 candidates is given by:
30C3 = 30! / (3! * (30-3)!) = 30! / (3! * 27!) = (30 * 29 * 28) / (3 * 2 * 1) = 4060
Therefore, there are 4060 ways to select 3 candidates out of 31 candidates if one candidate is always included.
b) If one candidate is always excluded, then we need to select 4 candidates out of 30 remaining candidates.
The number of ways to select 4 candidates out of 30 candidates is given by:
30C4 = 30! / (4! * (30-4)!) = 30! / (4! * 26!) = (30 * 29 * 28 * 27) / (4 * 3 * 2 * 1) = 27405
Therefore, there are 27405 ways to select 4 candidates out of 31 candidates if one candidate is always excluded.
Hence, the answer is option B.
In your office 4 posts have fallen vacant. In how many ways a selectio...
We have total options 31 from which we have to select on 4 person . but there is condition that 1 person is always selected . so now we have only 30 options . AND IN 30 options we have to select only 3 because 1 is already selected . I HOPE MY ANSWER IS HELPFUL FOR YOU.
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