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The area of a trapezium whose parallel sides are 77cm and 60cm and other side are 25cm and 26cm?
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The area of a trapezium whose parallel sides are 77cm and 60cm and oth...
Given a trapezium whose parallel sides are 77 cm and 60 cm and the other sides are 25 cm and 26 cm.

we have to find the area of trapezium.

AD=60 cm

BD=77 cm

AB=25 cm

DC=26 cm

EC=BC-BE=77-60=17 cm

In triangle DEC



By Heron's formula,

Answer 1644cm²
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The area of a trapezium whose parallel sides are 77cm and 60cm and oth...
Introduction:
A trapezium is a quadrilateral with only one pair of parallel sides. To find the area of a trapezium, we can use the formula:

Area = (1/2) × (a + b) × h

where 'a' and 'b' are the lengths of the parallel sides, and 'h' is the height or the perpendicular distance between the parallel sides.

Given:
Parallel sides of the trapezium: 77 cm and 60 cm
Other sides of the trapezium: 25 cm and 26 cm

Step 1: Find the height of the trapezium:
To find the height, we can use the Pythagorean theorem. The height forms a right-angled triangle with the two sides of length 25 cm and 26 cm.

Using the Pythagorean theorem, we have:
h² = (26 cm)² - (25 cm)²

h² = 676 - 625

h² = 51

h ≈ √51

h ≈ 7.14 cm


Therefore, the height of the trapezium is approximately 7.14 cm.

Step 2: Calculate the area:
Using the formula for the area of a trapezium, we substitute the values we have:
Area = (1/2) × (77 cm + 60 cm) × 7.14 cm
Area = (1/2) × (137 cm) × 7.14 cm
Area ≈ 488.79 cm²

Therefore, the area of the trapezium is approximately 488.79 cm².

Conclusion:
The area of the trapezium with parallel sides measuring 77 cm and 60 cm, and other sides measuring 25 cm and 26 cm, is approximately 488.79 cm².
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