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C6H5OH(g) + O2(g) → CO2(g) + H2O(l)
The magnitude of volume change if 30 ml of C6H5OH (g) is burnt with an excess amount of oxygen, is
- a)30 ml
- b)60 ml
- c)20 ml
- d)10 ml
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
C6H5OH(g) + O2(g) → CO2(g) + H2O(l)The magnitude of volume change...
Balanced Reaction: C6H5OH(g)+7O2(g) ——> 6CO2(g)+3H2O(l)
8 moles of the reactants get reduced to 9 moles of products.
Now, 30 ml of Phenol will react (30 x 7) = 210 ml of oxygen.
So, (30+210) = 240 ml of the reactants will after reaction will give = (30 x 6) + (30 x 3) = 270 ml of products.
Since the water formed is in the liquid state will not contribute to the volume increase, the resultant mixture will contain 270 ml.
So, the volume change is of 270 – 240 = 30 ml.
8 moles of the reactants get reduced to 9 moles of products.
Now, 30 ml of Phenol will react (30 x 7) = 210 ml of oxygen.
So, (30+210) = 240 ml of the reactants will after reaction will give = (30 x 6) + (30 x 3) = 270 ml of products.
Since the water formed is in the liquid state will not contribute to the volume increase, the resultant mixture will contain 270 ml.
So, the volume change is of 270 – 240 = 30 ml.
Most Upvoted Answer
C6H5OH(g) + O2(g) → CO2(g) + H2O(l)The magnitude of volume change...
This is not a chemical equation. It is missing the reactants and products. Please provide more information.
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C6H5OH(g) + O2(g) → CO2(g) + H2O(l)The magnitude of volume change if 30 ml of C6H5OH (g) is burnt with an excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer?
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C6H5OH(g) + O2(g) → CO2(g) + H2O(l)The magnitude of volume change if 30 ml of C6H5OH (g) is burnt with an excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about C6H5OH(g) + O2(g) → CO2(g) + H2O(l)The magnitude of volume change if 30 ml of C6H5OH (g) is burnt with an excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for C6H5OH(g) + O2(g) → CO2(g) + H2O(l)The magnitude of volume change if 30 ml of C6H5OH (g) is burnt with an excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer?.
C6H5OH(g) + O2(g) → CO2(g) + H2O(l)The magnitude of volume change if 30 ml of C6H5OH (g) is burnt with an excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about C6H5OH(g) + O2(g) → CO2(g) + H2O(l)The magnitude of volume change if 30 ml of C6H5OH (g) is burnt with an excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for C6H5OH(g) + O2(g) → CO2(g) + H2O(l)The magnitude of volume change if 30 ml of C6H5OH (g) is burnt with an excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer?.
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