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C6H5OH(g) + O2(g) → CO2(g) + H2O(l)
Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, is
- a)30 ml
- b)60 ml
- c)20 ml
- d)10 ml
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
C6H5OH(g) + O2(g) → CO2(g) + H2O(l)Magnitude of volume change if ...
The balanced chemical reaction is;
Usually such questions are asked by either saying the reaction is at STP,so you have to consider this in the mind
Step 1
Use PV = nRT to determine the moles of C6H5OH
Step 2
calculate the moles of H2O & CO2 are produced
for 1 mole of C6H5OH , 3 mole of H2O are produced
hence for 1.3387 moles,moles of H2O produced are = 1.3387 X 3
= 4.0161 moles
similarly,
since 1 mole of C6H5OH ,3 mole of CO2 are produced will be = 1.3387 X 6
= 8.0322 moles
Step 3
Use moles H2O & CO2 to convert it into volume
(a) Volume of H2O
1 atm X V ml = 4.0161 X 0.083 L atm/K/mol X 273K
=> Volume of H2O = 90ml
(b) Volume of CO2
1 atm X V ml = 8.0322 X 0.0823 L atm/K/mol X 273K
=>volume of CO2 = 180ml
hence change in volume = (180 + 90) – 30
= 240ml
This question is part of UPSC exam. View all Class 11 courses
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C6H5OH(g) + O2(g) → CO2(g) + H2O(l)Magnitude of volume change if ...
C6H5OH(g) + O2(g) → CO2(g) + H2O(g)
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C6H5OH(g) + O2(g) → CO2(g) + H2O(l)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer?
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C6H5OH(g) + O2(g) → CO2(g) + H2O(l)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about C6H5OH(g) + O2(g) → CO2(g) + H2O(l)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for C6H5OH(g) + O2(g) → CO2(g) + H2O(l)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer?.
C6H5OH(g) + O2(g) → CO2(g) + H2O(l)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about C6H5OH(g) + O2(g) → CO2(g) + H2O(l)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for C6H5OH(g) + O2(g) → CO2(g) + H2O(l)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30 mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer?.
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