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C6H5OH(g) + O2(g) → CO2(g) + H2O(/)
Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, is
Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, is
- a)30ml
- b)60 ml
- c)20 ml
- d)10 ml
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
C6H5OH(g) + O2(g) →CO2(g) + H2O(/)Magnitude of volume change if 3...
The reaction is not balanced. The balanced reaction is
C6H5OH (g) + 7O2(g) → 6CO2(g) + 3H2O(l)
Sinec water formed in liquid state, imts volume is considered to be 0.
Volume of C6H5OH = 30 mL
Since 1 volume of C6H5OH reacts with 7 volume of O2,
Volume of O2 = 7×30 = 210mL
7 moles of O2 forms 6 moles of CO2
1 moles of O2 forms 6/7 volume of CO2
210 mL forms 6/7 210 = 180mL
Volume change = (total volume)reactant - (total volume)product
= (30+210)-(180+0) = 60 mL
C6H5OH (g) + 7O2(g) → 6CO2(g) + 3H2O(l)
Sinec water formed in liquid state, imts volume is considered to be 0.
Volume of C6H5OH = 30 mL
Since 1 volume of C6H5OH reacts with 7 volume of O2,
Volume of O2 = 7×30 = 210mL
7 moles of O2 forms 6 moles of CO2
1 moles of O2 forms 6/7 volume of CO2
210 mL forms 6/7 210 = 180mL
Volume change = (total volume)reactant - (total volume)product
= (30+210)-(180+0) = 60 mL
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C6H5OH(g) + O2(g) →CO2(g) + H2O(/)Magnitude of volume change if 3...
This is not a balanced chemical equation. It is missing the products of the reaction. Please provide more information.
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C6H5OH(g) + O2(g) →CO2(g) + H2O(/)Magnitude of volume change if 3...
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C6H5OH(g) + O2(g) →CO2(g) + H2O(/)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer?
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C6H5OH(g) + O2(g) →CO2(g) + H2O(/)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about C6H5OH(g) + O2(g) →CO2(g) + H2O(/)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for C6H5OH(g) + O2(g) →CO2(g) + H2O(/)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer?.
C6H5OH(g) + O2(g) →CO2(g) + H2O(/)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about C6H5OH(g) + O2(g) →CO2(g) + H2O(/)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for C6H5OH(g) + O2(g) →CO2(g) + H2O(/)Magnitude of volume change if 30 ml of C6H5OH (g) is burnt with excess amount of oxygen, isa)30mlb)60 mlc)20 mld)10 mlCorrect answer is option 'B'. Can you explain this answer?.
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