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In which of the following pairs of solutions will the values of the vent Hoff factor be the same?
  • a)
    0.05 M K4[Fe(CN)6] and 0.10 M FeSO4
  • b)
    0.10 M K4[Fe(CN)6J and 0.05 M FeSO4(NH4)2SO4. 6H20
  • c)
    0.20 M NaCI and 0.10 M BaCl2
  • d)
    0.05 M FeSO4 (NH4)2SO4 6H20 and 0.02 M KCI . MgC12. 6H20
Correct answer is option 'B,D'. Can you explain this answer?
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In which of the following pairs of solutions will the values of the ve...
Number of particles from K4 [Fe(CN)6] = 5
                            Number of particles from FeSO4 (NH4)2 SO4 . 6H2O = 5
                            Number of particles from KCl. MgCl2. 8H2O = 5
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In which of the following pairs of solutions will the values of the ve...
Vent Hoff factor is a measure of the number of ions that a solute will produce in a solution. The values of the vent Hoff factor depend on the nature of the solute and the solvent.

a) 0.05 M K4[Fe(CN)6] and 0.10 M FeSO4:

- K4[Fe(CN)6] is a strong electrolyte and dissociates completely into four K+ ions and one [Fe(CN)6]4- ion.
- FeSO4 is also a strong electrolyte and dissociates completely into one Fe2+ ion and one SO42- ion.
- The vent Hoff factor for K4[Fe(CN)6] is 5, and for FeSO4, it is 2.
- Therefore, the values of the vent Hoff factor for these two solutions will not be the same.

b) 0.10 M K4[Fe(CN)6] and 0.05 M FeSO4(NH4)2SO4.6H20:

- K4[Fe(CN)6] is a strong electrolyte and dissociates completely into four K+ ions and one [Fe(CN)6]4- ion.
- FeSO4(NH4)2SO4.6H20 is a salt that dissociates into Fe2+, SO42-, NH4+, and H2O molecules.
- The vent Hoff factor for K4[Fe(CN)6] is 5, and for FeSO4(NH4)2SO4.6H20, it is 3.
- Therefore, the values of the vent Hoff factor for these two solutions will not be the same.

c) 0.20 M NaCI and 0.10 M BaCl2:

- NaCI is a strong electrolyte and dissociates completely into Na+ and Cl- ions.
- BaCl2 is also a strong electrolyte and dissociates completely into Ba2+ and 2 Cl- ions.
- The vent Hoff factor for NaCI is 2, and for BaCl2, it is 3.
- Therefore, the values of the vent Hoff factor for these two solutions will not be the same.

d) 0.05 M FeSO4(NH4)2SO4.6H20 and 0.02 M KCI.MgC12.6H20:

- FeSO4(NH4)2SO4.6H20 is a salt that dissociates into Fe2+, SO42-, NH4+, and H2O molecules.
- KCI.MgC12.6H20 is a salt that dissociates into K+, Cl-, Mg2+, and 6H2O molecules.
- The vent Hoff factor for FeSO4(NH4)2SO4.6H20 is 3, and for KCI.MgC12.6H20, it is 4.
- Therefore, the values of the vent Hoff factor for these two solutions will not be the same.

Hence, the correct options are B and D, where the values of the vent Hoff factor will be the same.
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A system of greater disorder of molecules is more probable. The disorder of molecules is reflected by the entropy of the system. A liquid vaporizes to form a more disordered gas. When a solulte is present , there is additional contribution to the entropy of the liquid due to increase randomness. As the entropy of solution is higher than that of pure liquid, there is weaker tendency to form the gas.Thus , a solute (non volatil e) lowers the vapour pressure of a liquid, and hence a higher booing point of the solution Similarly, the greater randomness of the solution opposes the tendency to freeze. In consequence, a lower the temperature must be reached for achieving the equilibrium between the solid (frozen solvent) and the solution . Elevation of B.Pt. Tband depression of F.Pt. Tfof a solution are the colligative properties which depend only on the concentration of particles of the solute, not their identity.For dilute solutions, Tband Tfare proportional to the molality of the solute in the solution.The vaues of Kb and Kf do depend on the properties of the solvent. For liquids, is almost constant . [Troutans Rule , this constant for most of the Unassociated liquids (not having any strong bonding like Hydrogen bonding in the liquid state) is equal to 90J/mol. ] For solutes undergoing change of molecular state is solution (ionization or association), the observed T values differ from the calculate ones using the above relations. In such situations, the relationships are modified as Where i = Vant Hoff factor, greater than unity for ionization and smaller than unity for association of the solute molecules.Q.Depression of freezing point of which of the following solutions does represent the cryoscopic constant of water?

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In which of the following pairs of solutions will the values of the vent Hoff factor be the same?a)0.05 M K4[Fe(CN)6] and 0.10 M FeSO4b)0.10 M K4[Fe(CN)6J and 0.05 M FeSO4(NH4)2SO4. 6H20c)0.20 M NaCI and 0.10 M BaCl2d)0.05 M FeSO4 (NH4)2SO4 6H20 and 0.02 M KCI . MgC12. 6H20Correct answer is option 'B,D'. Can you explain this answer?
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In which of the following pairs of solutions will the values of the vent Hoff factor be the same?a)0.05 M K4[Fe(CN)6] and 0.10 M FeSO4b)0.10 M K4[Fe(CN)6J and 0.05 M FeSO4(NH4)2SO4. 6H20c)0.20 M NaCI and 0.10 M BaCl2d)0.05 M FeSO4 (NH4)2SO4 6H20 and 0.02 M KCI . MgC12. 6H20Correct answer is option 'B,D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In which of the following pairs of solutions will the values of the vent Hoff factor be the same?a)0.05 M K4[Fe(CN)6] and 0.10 M FeSO4b)0.10 M K4[Fe(CN)6J and 0.05 M FeSO4(NH4)2SO4. 6H20c)0.20 M NaCI and 0.10 M BaCl2d)0.05 M FeSO4 (NH4)2SO4 6H20 and 0.02 M KCI . MgC12. 6H20Correct answer is option 'B,D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In which of the following pairs of solutions will the values of the vent Hoff factor be the same?a)0.05 M K4[Fe(CN)6] and 0.10 M FeSO4b)0.10 M K4[Fe(CN)6J and 0.05 M FeSO4(NH4)2SO4. 6H20c)0.20 M NaCI and 0.10 M BaCl2d)0.05 M FeSO4 (NH4)2SO4 6H20 and 0.02 M KCI . MgC12. 6H20Correct answer is option 'B,D'. Can you explain this answer?.
Solutions for In which of the following pairs of solutions will the values of the vent Hoff factor be the same?a)0.05 M K4[Fe(CN)6] and 0.10 M FeSO4b)0.10 M K4[Fe(CN)6J and 0.05 M FeSO4(NH4)2SO4. 6H20c)0.20 M NaCI and 0.10 M BaCl2d)0.05 M FeSO4 (NH4)2SO4 6H20 and 0.02 M KCI . MgC12. 6H20Correct answer is option 'B,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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