Two bar magnet if length 0.1m and pole strength 75Am each one placed o...
Two bar magnet if length 0.1m and pole strength 75Am each one placed o...
Problem Statement: Two bar magnets of length 0.1m and pole strength 75Am each are placed on the same line at a distance of 0.2m between their centers. Find the resultant force on one magnet due to the other when the north pole of one faces the south pole of the other and when the north pole of one faces the north pole of the other.
Solution:
Given Data:
Length of each magnet, L = 0.1m
Pole strength of each magnet, m = 75 Am
Distance between their centers, r = 0.2m
Resultant force between two bar magnets:
The force between two bar magnets is given by the formula:
F = (m₁m₂)/r²
Where, m₁ and m₂ are the pole strengths of the two magnets, and r is the distance between their centers.
Case 1: When north pole of one magnet faces the south pole of the other:
In this case, the force between the two magnets is attractive, and the magnets will move towards each other. The pole strength of the north pole is taken as positive and that of the south pole is taken as negative.
The force between two magnets is given by:
F = (m₁m₂)/r²
F = [(75)(-75)]/(0.2)²
F = -2812.5 N
The negative sign indicates that the force is attractive.
Case 2: When north pole of one magnet faces the north pole of the other:
In this case, the force between the two magnets is repulsive, and the magnets will move away from each other.
The force between two magnets is given by:
F = (m₁m₂)/r²
F = (75)(75)/(0.2)²
F = 2812.5 N
The positive sign indicates that the force is repulsive.
Conclusion:
Thus, the resultant force on one magnet due to the other when the north pole of one faces the south pole of the other is -2812.5 N (attractive), and when the north pole of one faces the north pole of the other is 2812.5 N (repulsive).