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The mean and SD for a,b and 2 are 3 and 2/√3 respectively , the value of ab would be?
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The mean and SD for a,b and 2 are 3 and 2/√3 respectively , the value ...
Solution:
Given, mean of a, b and 2 is 3
So, (a+b+2)/3 = 3
a+b = 7
Also, SD for a, b and 2 is 2/√3
So, (a-3)/2/√3 = (b-3)/2/√3 = (2-3)/2/√3
(a-3)/2 = (b-3)/2 = (-1)/2
a-3 = -b+3 = -1
a = b+2
Putting value of a in the above equation, we get
2b+2 = 7
b = 2.5
a = 4.5
Hence, ab = 4.5*2.5 = 11.25
Therefore, the value of ab is 11.25.
Given, mean of a, b and 2 is 3
So, (a+b+2)/3 = 3
a+b = 7
Also, SD for a, b and 2 is 2/√3
So, (a-3)/2/√3 = (b-3)/2/√3 = (2-3)/2/√3
(a-3)/2 = (b-3)/2 = (-1)/2
a-3 = -b+3 = -1
a = b+2
Putting value of a in the above equation, we get
2b+2 = 7
b = 2.5
a = 4.5
Hence, ab = 4.5*2.5 = 11.25
Therefore, the value of ab is 11.25.
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The mean and SD for a,b and 2 are 3 and 2/√3 respectively , the value of ab would be?
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The mean and SD for a,b and 2 are 3 and 2/√3 respectively , the value of ab would be? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The mean and SD for a,b and 2 are 3 and 2/√3 respectively , the value of ab would be? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The mean and SD for a,b and 2 are 3 and 2/√3 respectively , the value of ab would be?.
The mean and SD for a,b and 2 are 3 and 2/√3 respectively , the value of ab would be? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The mean and SD for a,b and 2 are 3 and 2/√3 respectively , the value of ab would be? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The mean and SD for a,b and 2 are 3 and 2/√3 respectively , the value of ab would be?.
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