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What will be the probable value of mean deviation if Q3 = 40, Q1= 15 a)17.50 b)18.75 c)15 d) none Please give ans with explanation?
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What will be the probable value of mean deviation if Q3 = 40, Q1= 15 a...
Probable value of mean deviation with Q3=40 and Q1=15
Mean deviation is the measure of dispersion which tells us how far, on average, the observations in a set of data are from the mean of the data. To calculate mean deviation, we need to first calculate the mean of the data and then subtract each observation from the mean and take the absolute value of each deviation. We then add up all these absolute deviations and divide by the number of observations.
Given Q3=40 and Q1=15, we can calculate the interquartile range (IQR) as Q3-Q1=40-15=25.
Now, we can use the following formula to calculate the probable value of mean deviation:
Mean deviation = (IQR/2) / (0.6745)
Where 0.6745 is a constant value obtained from standard normal distribution for the first quartile.
Substituting the values, we get:
Mean deviation = (25/2) / (0.6745)
Mean deviation = 18.596
Therefore, the probable value of mean deviation is option (b) 18.75.
Explanation:
- Calculation of interquartile range (IQR)
- Formula to calculate mean deviation
- Substitution of values in the formula
- Calculation of mean deviation
- Selection of correct option.
Mean deviation is the measure of dispersion which tells us how far, on average, the observations in a set of data are from the mean of the data. To calculate mean deviation, we need to first calculate the mean of the data and then subtract each observation from the mean and take the absolute value of each deviation. We then add up all these absolute deviations and divide by the number of observations.
Given Q3=40 and Q1=15, we can calculate the interquartile range (IQR) as Q3-Q1=40-15=25.
Now, we can use the following formula to calculate the probable value of mean deviation:
Mean deviation = (IQR/2) / (0.6745)
Where 0.6745 is a constant value obtained from standard normal distribution for the first quartile.
Substituting the values, we get:
Mean deviation = (25/2) / (0.6745)
Mean deviation = 18.596
Therefore, the probable value of mean deviation is option (b) 18.75.
Explanation:
- Calculation of interquartile range (IQR)
- Formula to calculate mean deviation
- Substitution of values in the formula
- Calculation of mean deviation
- Selection of correct option.
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What will be the probable value of mean deviation if Q3 = 40, Q1= 15 a)17.50 b)18.75 c)15 d) none Please give ans with explanation?
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What will be the probable value of mean deviation if Q3 = 40, Q1= 15 a)17.50 b)18.75 c)15 d) none Please give ans with explanation? for CA Foundation 2025 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about What will be the probable value of mean deviation if Q3 = 40, Q1= 15 a)17.50 b)18.75 c)15 d) none Please give ans with explanation? covers all topics & solutions for CA Foundation 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the probable value of mean deviation if Q3 = 40, Q1= 15 a)17.50 b)18.75 c)15 d) none Please give ans with explanation?.
What will be the probable value of mean deviation if Q3 = 40, Q1= 15 a)17.50 b)18.75 c)15 d) none Please give ans with explanation? for CA Foundation 2025 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about What will be the probable value of mean deviation if Q3 = 40, Q1= 15 a)17.50 b)18.75 c)15 d) none Please give ans with explanation? covers all topics & solutions for CA Foundation 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the probable value of mean deviation if Q3 = 40, Q1= 15 a)17.50 b)18.75 c)15 d) none Please give ans with explanation?.
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