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In [Cr(O2)(NH3)4 (H2O)] Cl2 oxidation number of Cr is + 3, then O2 will be in the form :
  • a)
    dioxide
  • b)
    peroxide
  • c)
    superoxide
  • d)
    oxide
Correct answer is option 'C'. Can you explain this answer?
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In [Cr(O2)(NH3)4(H2O)] Cl2oxidation number of Cr is + 3, then O2will b...
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In [Cr(O2)(NH3)4(H2O)] Cl2oxidation number of Cr is + 3, then O2will be in the form :a)dioxideb)peroxidec)superoxided)oxideCorrect answer is option 'C'. Can you explain this answer?
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In [Cr(O2)(NH3)4(H2O)] Cl2oxidation number of Cr is + 3, then O2will be in the form :a)dioxideb)peroxidec)superoxided)oxideCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In [Cr(O2)(NH3)4(H2O)] Cl2oxidation number of Cr is + 3, then O2will be in the form :a)dioxideb)peroxidec)superoxided)oxideCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In [Cr(O2)(NH3)4(H2O)] Cl2oxidation number of Cr is + 3, then O2will be in the form :a)dioxideb)peroxidec)superoxided)oxideCorrect answer is option 'C'. Can you explain this answer?.
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