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Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v :
 
  • a)
    1 m/s
  • b)
    2 m/s
  • c)
    3 m/s
  • d)
    4 m/s
Correct answer is option 'B'. Can you explain this answer?
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Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer?
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Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer?.
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