Question Description
Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer?.

Solutions for Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Two sound sources are moving in opposite directions with velocities v1 and v2 (v1 > v2). Bothe are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v1 – v2 so that the beat frequency observed by the observer is 6 Hz ? Speed of sound v=300m/s.Given that v1 and v2<< v:a)1 m/sb)2 m/sc)3 m/sd)4 m/sCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.