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In a series CR circuit shown in figure, the applied voltage is 10 V and the voltage across capacitor is found to be 8V. Then the voltage across R, and the phase difference between current and the applied voltage will respectively be
                 
  • a)
    6V, tan-1 
  • b)
    3V, tan-1  
  • c)
    6V, tan-1  
  • d)
    None
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In a series CR circuit shown in figure, the applied voltage is 10 V an...
VR​=√ [V2−VC2​​]=√ [(10)2−(8)2]​=6V
tanϕ= XC/XR​ ​​= VC​​/VR​ =8/6​=4/3​
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In a series CR circuit shown in figure, the applied voltage is 10 V and the voltage across capacitor is found to be 8V. Then the voltage across R, and the phase difference between current and the applied voltage will respectively be a)6V, tan-1b)3V, tan-1c)6V, tan-1d)NoneCorrect answer is option 'A'. Can you explain this answer?
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