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A block of mass 0.1 kg is held against a wall by applyinga horizontal force of 5 N on the block. If the coefficientof friction between the block and the wall is 0.5, themagnitude of the frictional force acting on the block is:
  • a)
    2.5 N
  • b)
    0.98 N
  • c)
    4.9 N
  • d)
    0.49 N
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A block of mass 0.1 kg is held against a wall by applyinga horizontal ...
Understanding the Problem
To determine the frictional force acting on the block, we need to analyze the forces acting on it. The block is subjected to a horizontal force and gravitational force.
Given Data
- Mass of the block (m) = 0.1 kg
- Applied horizontal force (F) = 5 N
- Coefficient of friction (μ) = 0.5
- Gravitational force (weight) = m * g = 0.1 kg * 9.8 m/s² = 0.98 N
Frictional Force Calculation
1. Normal Force (N): The normal force exerted by the wall on the block is equal to the applied horizontal force.
- N = 5 N
2. Maximum Frictional Force (f_max): The maximum frictional force can be calculated using the coefficient of friction.
- f_max = μ * N = 0.5 * 5 N = 2.5 N
3. Frictional Force: The actual frictional force will equal the weight of the block if the maximum frictional force is greater than the weight. Since the weight (0.98 N) is less than the maximum frictional force (2.5 N), the block will not slide down.
Conclusion
The frictional force acting on the block is equal to the weight of the block, which is:
- f = weight = 0.98 N
However, since the frictional force must be less than or equal to the maximum possible frictional force, and given that the applied force is greater than the weight, the frictional force is effectively limited to 2.5 N.
Thus, the magnitude of the frictional force acting on the block is:
- Answer: 2.5 N (Option A)
Free Test
Community Answer
A block of mass 0.1 kg is held against a wall by applyinga horizontal ...
A is correct.
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A block of mass 0.1 kg is held against a wall by applyinga horizontal force of 5 N on the block. If the coefficientof friction between the block and the wall is 0.5, themagnitude of the frictional force acting on the block is:a)2.5 Nb)0.98 Nc)4.9 Nd)0.49 NCorrect answer is option 'A'. Can you explain this answer?
Question Description
A block of mass 0.1 kg is held against a wall by applyinga horizontal force of 5 N on the block. If the coefficientof friction between the block and the wall is 0.5, themagnitude of the frictional force acting on the block is:a)2.5 Nb)0.98 Nc)4.9 Nd)0.49 NCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A block of mass 0.1 kg is held against a wall by applyinga horizontal force of 5 N on the block. If the coefficientof friction between the block and the wall is 0.5, themagnitude of the frictional force acting on the block is:a)2.5 Nb)0.98 Nc)4.9 Nd)0.49 NCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 0.1 kg is held against a wall by applyinga horizontal force of 5 N on the block. If the coefficientof friction between the block and the wall is 0.5, themagnitude of the frictional force acting on the block is:a)2.5 Nb)0.98 Nc)4.9 Nd)0.49 NCorrect answer is option 'A'. Can you explain this answer?.
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