Force of Pull to Cause Sliding of a Block

Given information:
- Mass of the block (m) = 50 kg
- Coefficient of friction (μ) = 0.6

To calculate the least force of pull that will cause the block to just slide, we need to consider the forces acting on the block and determine the minimum force required to overcome the frictional force.

1. Identify the forces acting on the block:
- Weight of the block (mg): This force acts vertically downwards and is equal to the mass of the block multiplied by the acceleration due to gravity (9.8 m/s²).
- Normal force (N): This force acts perpendicular to the surface and is equal to the weight of the block (mg) in the absence of any vertical acceleration.
- Frictional force (f): This force acts parallel to the surface and opposes the motion of the block. It is given by the product of the coefficient of friction (μ) and the normal force (N).

2. Calculate the weight of the block:
Weight (mg) = mass (m) × acceleration due to gravity (g)
Weight = 50 kg × 9.8 m/s²
Weight = 490 N

3. Calculate the normal force:
The normal force (N) is equal to the weight of the block when there is no vertical acceleration.
Normal force (N) = Weight (mg)
Normal force = 490 N

4. Calculate the frictional force:
Frictional force (f) = coefficient of friction (μ) × normal force (N)
Frictional force = 0.6 × 490 N
Frictional force = 294 N

5. Determine the least force of pull:
The least force of pull required to cause the block to just slide is equal to the frictional force.
Force of pull = Frictional force
Force of pull = 294 N

Therefore, the least force of pull that will cause the block to just slide is 294 N.