A mixture of methane and ethene in molar ratio of x:y has an average m...
Given information:
- Molar ratio of methane and ethene = x:y
- Average molecular mass = 20u
To find:
- Mean molar mass when mixed in ratio of y:x
Approach:
1. Find the molecular mass of methane and ethene using their atomic masses.
2. Use the given molar ratio to calculate the weighted average molecular mass of the mixture.
3. Use the formula for mean molar mass to find the answer.
Calculation:
1. Molecular mass of methane (CH4) = 12 + 4(1) = 16u
Molecular mass of ethene (C2H4) = 2(12) + 4(1) = 28u
2. Let the number of moles of methane be x and the number of moles of ethene be y.
Then, the weighted average molecular mass of the mixture can be calculated as:
(x*16 + y*28)/(x+y) = 20
Solving for y/x, we get:
y/x = 3/4
3. Now, we need to find the mean molar mass when the molar ratio is y:x.
Let the number of moles of ethene be p and the number of moles of methane be q.
Then, using the formula for mean molar mass, we get:
Mean molar mass = (p*28 + q*16)/(p+q)
Substituting y/x = 3/4, we can express p/q in terms of y/x as:
p/q = (y/x)/(1 - y/x) = 3/1
Therefore, we get:
Mean molar mass = (3*28 + 1*16)/(3+1) = 24u
Answer:
The mean molar mass when methane and ethene are mixed in the ratio of y:x is 24u. Therefore, the correct option is C.
A mixture of methane and ethene in molar ratio of x:y has an average m...