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A random variable x follows Binomial distribution with mean 2 and variance 1.2.Then the value of n is
  • a)
    8
  • b)
    2
  • c)
    5
  • d)
    none
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A random variable x follows Binomial distribution with mean 2 and vari...
Binomial Distribution

Binomial distribution is a discrete probability distribution that describes the number of successes in a fixed number of independent trials, each with the same probability of success. It has two parameters, n and p, where n is the number of trials and p is the probability of success in each trial.

Mean and Variance of Binomial Distribution

The mean and variance of a binomial distribution are given by:

Mean = np
Variance = np(1-p)

Solution

Given, mean = 2 and variance = 1.2

Mean = np = 2
Variance = np(1-p) = 1.2

Substituting np = 2 in the variance equation, we get:

2(1-p) = 1.2
2 - 2p = 1.2
-2p = -0.8
p = 0.4

Substituting p = 0.4 in the mean equation, we get:

np = 2
n(0.4) = 2
n = 5

Therefore, the value of n is 5, which is option C.
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Community Answer
A random variable x follows Binomial distribution with mean 2 and vari...
Given np=2 & npq=1.2
(2)q=1.2
q=0.6
p= 1-q=0.4
n(0.4)=2
n=5
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A random variable x follows Binomial distribution with mean 2 and variance 1.2.Then the value of n isa)8b)2c)5d)noneCorrect answer is option 'C'. Can you explain this answer?
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