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The random variable X follows a normal distribution with name two and variable = 1.6 then the value of p is a) 1/5 b) 4/5 c) 3/5 d) None?
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The random variable X follows a normal distribution with name two and ...
Given Information:

  • Random variable X follows normal distribution with name two and variable = 1.6.



To find: Value of p.

Solution:

  • We know that the standard normal distribution has a mean of 0 and a standard deviation of 1.

  • Any normal distribution can be standardized by subtracting the mean and dividing by the standard deviation.

  • Let Z be a standard normal variable.



Formula:

  • Z = (X - μ) / σ



Where,

  • X = normal distribution variable

  • μ = mean of the normal distribution

  • σ = standard deviation of the normal distribution



Calculation:

  • Given, variable of normal distribution X = 1.6

  • Let mean of the normal distribution be μ and standard deviation be σ.



Since, Z is standard normal variable, we have:

Z = (X - μ) / σ

Z = (1.6 - μ) / σ

As per the question, X follows a normal distribution with name two. For a standard normal distribution, the proportion of values less than 0 is 0.5.

So, P(Z < 0)="" />

Substituting the value of Z in the above equation, we get:

P((1.6 - μ) / σ < 0)="" />

Solving for μ, we get:

μ > 1.6

This means that the mean of the normal distribution is greater than 1.6.

Now, we can use the standard normal distribution table to find the probability of Z being less than 0. To do so, we need to find the value of Z corresponding to μ = 1.6 and σ = 1.

Z = (X - μ) / σ

Z = (1.6 - 1) / 1

Z = 0.6

From the standard normal distribution table, we can see that the probability of Z being less than 0.6 is approximately 0.7257.

Therefore, the value of p is:

P(Z < 0.6)="" />

Hence, the answer is option (d) None as none of the given options match the calculated value of p.
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The random variable X follows a normal distribution with name two and variable = 1.6 then the value of p is a) 1/5 b) 4/5 c) 3/5 d) None?
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