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A rectangular tank of base 3 m × 3 m contains oil of specific gravity 0.8 upto a height of 8 m. When it is accelerated at 2.45 m/s^2 vertically upwards, the force on the base of the tank will be: [IAS-1999/ME]?
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A rectangular tank of base 3 m × 3 m contains oil of specific gravity ...
Problem
A rectangular tank of base 3 m × 3 m contains oil of specific gravity 0.8 upto a height of 8 m. When it is accelerated at 2.45 m/s^2 vertically upwards, the force on the base of the tank will be:
Solution
Given data:
Base of the tank = 3 m × 3 m
Height of the oil = 8 m
Specific gravity of oil = 0.8
Acceleration = 2.45 m/s^2
Step 1: Calculate the weight of oil
The weight of oil can be calculated using the following formula:
Weight of oil = Volume of oil × Specific gravity of oil × Acceleration due to gravity
The volume of oil can be calculated as follows:
Volume of oil = Base area of tank × Height of oil
Volume of oil = 3 m × 3 m × 8 m
Volume of oil = 72 m^3
Weight of oil = 72 m^3 × 0.8 × 9.81 m/s^2
Weight of oil = 564.096 N
Step 2: Calculate the force on the base of the tank
The force on the base of the tank can be calculated using the following formula:
Force = Weight of oil + Mass of tank × Acceleration
The mass of the tank can be calculated as follows:
Mass of tank = Density of tank × Volume of tank
Assuming the density of the tank to be 7850 kg/m^3, the mass of the tank can be calculated as follows:
Mass of tank = 7850 kg/m^3 × 3 m × 3 m × 8 m
Mass of tank = 565440 kg
Force = 564.096 N + 565440 kg × 2.45 m/s^2
Force = 1389360 N
Therefore, the force on the base of the tank will be 1389360 N when it is accelerated at 2.45 m/s^2 vertically upwards.
A rectangular tank of base 3 m × 3 m contains oil of specific gravity 0.8 upto a height of 8 m. When it is accelerated at 2.45 m/s^2 vertically upwards, the force on the base of the tank will be:
Solution
Given data:
Base of the tank = 3 m × 3 m
Height of the oil = 8 m
Specific gravity of oil = 0.8
Acceleration = 2.45 m/s^2
Step 1: Calculate the weight of oil
The weight of oil can be calculated using the following formula:
Weight of oil = Volume of oil × Specific gravity of oil × Acceleration due to gravity
The volume of oil can be calculated as follows:
Volume of oil = Base area of tank × Height of oil
Volume of oil = 3 m × 3 m × 8 m
Volume of oil = 72 m^3
Weight of oil = 72 m^3 × 0.8 × 9.81 m/s^2
Weight of oil = 564.096 N
Step 2: Calculate the force on the base of the tank
The force on the base of the tank can be calculated using the following formula:
Force = Weight of oil + Mass of tank × Acceleration
The mass of the tank can be calculated as follows:
Mass of tank = Density of tank × Volume of tank
Assuming the density of the tank to be 7850 kg/m^3, the mass of the tank can be calculated as follows:
Mass of tank = 7850 kg/m^3 × 3 m × 3 m × 8 m
Mass of tank = 565440 kg
Force = 564.096 N + 565440 kg × 2.45 m/s^2
Force = 1389360 N
Therefore, the force on the base of the tank will be 1389360 N when it is accelerated at 2.45 m/s^2 vertically upwards.
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A rectangular tank of base 3 m × 3 m contains oil of specific gravity 0.8 upto a height of 8 m. When it is accelerated at 2.45 m/s^2 vertically upwards, the force on the base of the tank will be: [IAS-1999/ME]?
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A rectangular tank of base 3 m × 3 m contains oil of specific gravity 0.8 upto a height of 8 m. When it is accelerated at 2.45 m/s^2 vertically upwards, the force on the base of the tank will be: [IAS-1999/ME]? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A rectangular tank of base 3 m × 3 m contains oil of specific gravity 0.8 upto a height of 8 m. When it is accelerated at 2.45 m/s^2 vertically upwards, the force on the base of the tank will be: [IAS-1999/ME]? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular tank of base 3 m × 3 m contains oil of specific gravity 0.8 upto a height of 8 m. When it is accelerated at 2.45 m/s^2 vertically upwards, the force on the base of the tank will be: [IAS-1999/ME]?.
A rectangular tank of base 3 m × 3 m contains oil of specific gravity 0.8 upto a height of 8 m. When it is accelerated at 2.45 m/s^2 vertically upwards, the force on the base of the tank will be: [IAS-1999/ME]? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A rectangular tank of base 3 m × 3 m contains oil of specific gravity 0.8 upto a height of 8 m. When it is accelerated at 2.45 m/s^2 vertically upwards, the force on the base of the tank will be: [IAS-1999/ME]? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular tank of base 3 m × 3 m contains oil of specific gravity 0.8 upto a height of 8 m. When it is accelerated at 2.45 m/s^2 vertically upwards, the force on the base of the tank will be: [IAS-1999/ME]?.
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