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A particle of mass m is moving in a horizontal circle of radius R with uniform speed v. When it moves from one point to a diametrically opposite point its
  • a)
    kinetic energy changes by Mv2/4
  • b)
    momentum changes by 2Mv
  • c)
     momentum does not change
  • d)
    kinetic energy changes by Mv2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A particle ofmass m is moving in a horizontal circle of radius R with ...
On the diametrically opposite points, the velocities have same magnitude but opposite directions. Therefore change in momentum is
Mv - (-Mv) = 2Mv
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