The letters of the words CALCUTTA and AMERICA are arranged in all poss...
We are asked to find the ratio of the number of arrangements of the letters of the words "CALCUTTA" and "AMERICA."
Step 1: Number of Arrangements of CALCUTTA
The word "CALCUTTA" consists of 8 letters in total: C, A, L, C, U, T, T, A.
The repeated letters are:
- "C" appears 2 times,
- "A" appears 2 times,
- "T" appears 2 times.
The number of distinct arrangements of the letters of "CALCUTTA" is given by the formula for permutations of a multiset:
Arrangements of CALCUTTA = π / (2! × 2! × 2!)
Calculating:
Arrangements of CALCUTTA = (8!) / (2! × 2! × 2!) = 40320 / 8 = 5040
Step 2: Number of Arrangements of AMERICA
The word "AMERICA" consists of 7 letters: A, M, E, R, I, C, A.
The letter "A" repeats 2 times.
The number of distinct arrangements of the letters of "AMERICA" is:
Arrangements of AMERICA = π / (2!)
Calculating:
Arrangements of AMERICA = (7!) / (2!) = 5040 / 2 = 2520
Step 3: Finding the Ratio
The ratio of the number of arrangements of "CALCUTTA" to "AMERICA" is:
Ratio = (5040) / (2520) = 2:1
Thus, the ratio of the number of arrangements is 2 : 1.