JEE Exam > JEE Questions > If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^...
Start Learning for Free
If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please?
Most Upvoted Answer
If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value ...
To solve this problem, we can use the method of comparing coefficients.
First, let's expand the given equation:
5x^6 - 9x^2 + 1 = (px^4 + qx^3 + rx^2 + sx + t)(ax^2 + bx + c)
Now, we need to multiply the factors on the right-hand side to obtain the expanded form. We can do this by multiplying each term in the first factor (px^4 + qx^3 + rx^2 + sx + t) by each term in the second factor (ax^2 + bx + c).
Expanding the multiplication, we have:
5x^6 - 9x^2 + 1 = (ap)x^6 + (aq + bp)x^5 + (ar + bq + cp)x^4 + (as + br + cq)x^3 + (at + bs + cr)x^2 + (bt + cs)x + ct
Now, let's compare the coefficients of each power of x on both sides of the equation.
For the coefficient of x^6:
On the left-hand side, the coefficient is 5.
On the right-hand side, the coefficient is ap.
Comparing these coefficients, we can conclude that ap = 5.
Therefore, the answer is option a) 5.
First, let's expand the given equation:
5x^6 - 9x^2 + 1 = (px^4 + qx^3 + rx^2 + sx + t)(ax^2 + bx + c)
Now, we need to multiply the factors on the right-hand side to obtain the expanded form. We can do this by multiplying each term in the first factor (px^4 + qx^3 + rx^2 + sx + t) by each term in the second factor (ax^2 + bx + c).
Expanding the multiplication, we have:
5x^6 - 9x^2 + 1 = (ap)x^6 + (aq + bp)x^5 + (ar + bq + cp)x^4 + (as + br + cq)x^3 + (at + bs + cr)x^2 + (bt + cs)x + ct
Now, let's compare the coefficients of each power of x on both sides of the equation.
For the coefficient of x^6:
On the left-hand side, the coefficient is 5.
On the right-hand side, the coefficient is ap.
Comparing these coefficients, we can conclude that ap = 5.
Therefore, the answer is option a) 5.
Community Answer
If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value ...
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please?
Question Description
If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please?.
If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please?.
Solutions for If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please? defined & explained in the simplest way possible. Besides giving the explanation of
If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please?, a detailed solution for If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please? has been provided alongside types of If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please? theory, EduRev gives you an
ample number of questions to practice If 5x^6-9x^2 +1=(px^4+ qx^3 +rx^2 +sx+ t)(ax^2 +bx+ c) then the value of ap is a) 5 b) - 9 c) 6 d) - 3? any one solve this problem please? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup