If f(x) =an (x^n) +an-1( x^n-1) +... +a1(x) +ao and if( a1-ao)+ (a3-a2...
Explanation:
The given function can be written as:
f(x) = anx^n + an-1x^n-1 + ... + a1x + ao
We need to find one of the factors of the given function f(x) based on the condition that:
(a1-ao) (a3-a2) ... = 0
Solution:
We know that (a1-ao) (a3-a2) ... = 0. This means that either one of the factors is equal to 0 or all the factors are equal to 0.
If one of the factors is equal to 0, then we can say that:
a1 - ao = 0 or a3 - a2 = 0 or ...
This means that there exists a value of x for which f(x) = 0. Therefore, (x - k) is a factor of f(x), where k is the value for which f(k) = 0.
Let us take an example to understand this:
If (a1 - ao) = 0, then we have:
f(x) = anx^n + an-1x^n-1 + ... + aox + ao
Since (a1 - ao) = 0, we have a1 = ao.
Therefore, we can write:
f(x) = ao(x^n-1 + x^n-2 + ... + x + 1)
Now, we know that x^n-1 + x^n-2 + ... + x + 1 is a factor of x^n+1.
Therefore, we can write:
f(x) = ao(x^n+1)/(x+1)
This means that (x+1) is a factor of f(x).
Similarly, we can prove that (x-1), (x^2+1), and (x^2-1) are also factors of f(x).
Therefore, the answer is (d) (x^2-1).