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The solubility of AgI in NaI solution is less than that in pure water because
- a)AgI forms complex with NaI
- b)of common ion effect
- c)Solubility product of AgI is less than that of NaI
- d)the temperature of the solution decreases
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The solubility of AgI in NaI solution is less than that in pure water ...
Explanation:
- Common Ion Effect: When AgI is introduced into a solution containing NaI, the presence of I- ions from NaI will shift the equilibrium of AgI dissolution reaction to the left. This is due to the common ion effect, where the presence of a common ion (I-) reduces the solubility of AgI in the solution. Therefore, the solubility of AgI in NaI solution is less than that in pure water.
Most Upvoted Answer
The solubility of AgI in NaI solution is less than that in pure water ...
Explanation:
Common ion effect:
- When AgI is added to a solution of NaI, the concentration of I- ions increases due to the dissociation of NaI into Na+ and I- ions.
- This increase in the concentration of I- ions leads to a shift in the equilibrium of the dissolution of AgI towards the formation of AgI precipitate.
- The common ion effect reduces the solubility of AgI in the presence of NaI compared to its solubility in pure water.
Effect on solubility product:
- Solubility product (Ksp) is a measure of the solubility of a compound in a solution.
- The solubility product of AgI is lower than that of NaI, indicating that AgI is less soluble than NaI in a given solvent.
- This difference in solubility products also contributes to the lower solubility of AgI in NaI solution compared to pure water.
Conclusion:
- The common ion effect and the difference in solubility products play a significant role in reducing the solubility of AgI in NaI solution compared to its solubility in pure water.
- Therefore, the solubility of AgI in NaI solution is less due to the common ion effect and the lower solubility product of AgI.
Common ion effect:
- When AgI is added to a solution of NaI, the concentration of I- ions increases due to the dissociation of NaI into Na+ and I- ions.
- This increase in the concentration of I- ions leads to a shift in the equilibrium of the dissolution of AgI towards the formation of AgI precipitate.
- The common ion effect reduces the solubility of AgI in the presence of NaI compared to its solubility in pure water.
Effect on solubility product:
- Solubility product (Ksp) is a measure of the solubility of a compound in a solution.
- The solubility product of AgI is lower than that of NaI, indicating that AgI is less soluble than NaI in a given solvent.
- This difference in solubility products also contributes to the lower solubility of AgI in NaI solution compared to pure water.
Conclusion:
- The common ion effect and the difference in solubility products play a significant role in reducing the solubility of AgI in NaI solution compared to its solubility in pure water.
- Therefore, the solubility of AgI in NaI solution is less due to the common ion effect and the lower solubility product of AgI.
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The solubility of AgI in NaI solution is less than that in pure water becausea)AgI forms complex with NaIb)of common ion effectc)Solubility product of AgI is less than that of NaId)the temperature of the solution decreasesCorrect answer is option 'B'. Can you explain this answer?
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