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Let p(x) be a real polynomial of least degree which has a local maximum at x = 1 and a local minimum at x
= 3. If p(1) = 6 and p(3) = 2, then p'(0) is
    Correct answer is '9'. Can you explain this answer?
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    Given Information:
    - p(x) is a real polynomial of least degree.
    - p(x) has a local maximum at x = 1 and a local minimum at x = 3.
    - p(1) = 6 and p(3) = 2.

    Local Maximum and Minimum:
    - A local maximum occurs at a point where the function reaches its highest value in a small interval around that point.
    - Similarly, a local minimum occurs at a point where the function reaches its lowest value in a small interval around that point.

    Properties of Local Maximum and Minimum:
    - At a local maximum or minimum, the derivative of the function is zero or undefined.
    - At a local maximum, the second derivative of the function is negative.
    - At a local minimum, the second derivative of the function is positive.

    Derivative of p(x):
    - Since p(x) is a polynomial, it is differentiable for all values of x.
    - The derivative of p(x) gives the slope of the tangent line to the graph of p(x) at any point.
    - At the local maximum and minimum points, the derivative of p(x) is zero.

    Using the given information:
    - The derivative of p(x) is zero at x = 1 and x = 3.
    - Let's assume the degree of p(x) is n.
    - Since p(x) is a polynomial of least degree, it means p(x) is a polynomial of degree n.
    - The derivative of p(x) is a polynomial of degree (n-1).
    - Therefore, p'(x) has at least two roots, x = 1 and x = 3.
    - Since p'(x) has degree (n-1), it can have at most (n-1) roots.

    Inferring the degree of p(x):
    - Since p'(x) has at least two roots (x = 1 and x = 3), the degree of p'(x) is at least 2.
    - Therefore, the degree of p(x) is at least 3.

    Form of p(x):
    - The form of p(x) can be written as p(x) = a(x - 1)(x - 3)(x - c) where a is a constant and c is a real number.
    - This form satisfies the conditions of having a local maximum at x = 1 and a local minimum at x = 3.

    Using p(1) = 6 and p(3) = 2:
    - Plug in x = 1 and x = 3 into the form of p(x).
    - p(1) = a(1 - 1)(1 - 3)(1 - c) = 0
    - p(3) = a(3 - 1)(3 - 3)(3 - c) = 0
    - Since p(1) = 6 and p(3) = 2, the only possibility is that (1 - c) = -2 and (3 - c) = 2.
    - Solving the equations, we get c = 3.

    Calculating p(0):
    - Plug in x = 0 into the form of p(x).
    - p(0) = a(0
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    Let p(x) be a real polynomial of least degree which has a local maximum at x = 1 and a local minimum at x= 3. If p(1) = 6 and p(3) = 2, then p(0) isCorrect answer is '9'. Can you explain this answer?
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    Let p(x) be a real polynomial of least degree which has a local maximum at x = 1 and a local minimum at x= 3. If p(1) = 6 and p(3) = 2, then p(0) isCorrect answer is '9'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let p(x) be a real polynomial of least degree which has a local maximum at x = 1 and a local minimum at x= 3. If p(1) = 6 and p(3) = 2, then p(0) isCorrect answer is '9'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let p(x) be a real polynomial of least degree which has a local maximum at x = 1 and a local minimum at x= 3. If p(1) = 6 and p(3) = 2, then p(0) isCorrect answer is '9'. Can you explain this answer?.
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