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A group of certain number of man can complete a job in 5 days.on every alternate day starting from second day.3 men are withdrawn from the job and on every alternate day starting from third day, 2 men are added.if job is completed in 6 days, what is the number of persons who started the job.?
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A group of certain number of man can complete a job in 5 days.on every...
Problem: A group of certain number of men can complete a job in 5 days. On every alternate day starting from the second day, 3 men are withdrawn from the job and on every alternate day starting from the third day, 2 men are added. If the job is completed in 6 days, what is the number of persons who started the job?

Assumption: Let the initial number of men be x.

Solution:

  • Calculation of work done by the initial group of men:


    • Let the total work be 1 unit.

    • Then, the work done by x men in 1 day = 1/5x.

    • Therefore, the work done by x men in 2 days = 2/5x.



  • Calculation of work done by the group after withdrawal and addition of men:


    • On the 2nd day, 3 men are withdrawn, so the number of men working on the 2nd day = x - 3.

    • The work done by (x - 3) men on the 2nd day = 1/5(x - 3).

    • On the 3rd day, 2 men are added, so the number of men working on the 3rd day = (x - 3) + 2 = x - 1.

    • The work done by (x - 1) men on the 3rd day = 1/5(x - 1).

    • Similarly, on the 4th day, the number of men working = (x - 1) - 3 = x - 4.

    • The work done by (x - 4) men on the 4th day = 1/5(x - 4).

    • On the 5th day, the number of men working = (x - 4) + 2 = x - 2.

    • The work done by (x - 2) men on the 5th day = 1/5(x - 2).

    • On the 6th day, the number of men working = (x - 2) - 3 = x - 5.

    • The work done by (x - 5) men on the 6th day = 1/5(x - 5).



  • Calculation of total work done:


    • The total work done by the initial group of men and the group after withdrawal and addition of men can be equated to 1, as the entire job is completed.

    • Therefore, 2/5x + 1/5(x - 3) + 1/5(x - 1) + 1/5(x - 4) + 1/5(x - 2) + 1/5(x - 5) = 1.

    • Simplifying the above equation, we get:

    • 6x - 30 = 5x - 5.

    • Therefore, x = 25.
Community Answer
A group of certain number of man can complete a job in 5 days.on every...
Let number of men=x
then total work=5x. ....(1)
as per que
let x in men starts the job
every second day -3
every third day +2

day men
1. x
2. x-3
3. x-1
4. x-4
5. x-2
6. x-5
total work. 6x-15 (2)
so from 1 n 2
6x-15=5x
x=15
15 men had started the job
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A group of certain number of man can complete a job in 5 days.on every alternate day starting from second day.3 men are withdrawn from the job and on every alternate day starting from third day, 2 men are added.if job is completed in 6 days, what is the number of persons who started the job.?
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A group of certain number of man can complete a job in 5 days.on every alternate day starting from second day.3 men are withdrawn from the job and on every alternate day starting from third day, 2 men are added.if job is completed in 6 days, what is the number of persons who started the job.? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about A group of certain number of man can complete a job in 5 days.on every alternate day starting from second day.3 men are withdrawn from the job and on every alternate day starting from third day, 2 men are added.if job is completed in 6 days, what is the number of persons who started the job.? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A group of certain number of man can complete a job in 5 days.on every alternate day starting from second day.3 men are withdrawn from the job and on every alternate day starting from third day, 2 men are added.if job is completed in 6 days, what is the number of persons who started the job.?.
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