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The frequency changes by 10% as the source approaches a stationary observer with constant speed vs. What would be the percentage change in frequency as the source recedes the observer with the same speed ? Given, that vs « v ( v = speed of sound in air)a)16.7%b)8.5%c)14.3%d)20%Correct answer is option 'B'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared
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