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In a ration shop queue 2 boys, 2 girls, and 2 men are standing in such a way that the boys the girls and the men are together each.The total number of ways of arranging the queue is _______.
- a)42
- b)48
- c)24
- d)None
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In a ration shop queue 2 boys, 2 girls, and 2 men are standing in such...
Given:
- 2 boys
- 2 girls
- 2 men
They need to be arranged in such a way that the boys, girls, and men are together.
To solve this problem, we can use the concept of permutation.
Solution:
Step 1: Find the number of ways to arrange the boys, girls, and men separately.
- The 2 boys can be arranged in 2! ways.
- The 2 girls can be arranged in 2! ways.
- The 2 men can be arranged in 2! ways.
Step 2: Find the number of ways to arrange the groups of boys, girls, and men.
- Since the boys, girls, and men need to be together, we can treat each group as a single entity.
- Therefore, there are 3 entities to arrange: the group of boys, the group of girls, and the group of men.
- These 3 entities can be arranged in 3! ways.
Step 3: Find the total number of ways to arrange the queue.
- Multiply the results from Step 1 and Step 2 to get the total number of ways.
- Total number of ways = 2! x 2! x 2! x 3! = 48
Therefore, the total number of ways to arrange the queue is 48, which is option (B).
- 2 boys
- 2 girls
- 2 men
They need to be arranged in such a way that the boys, girls, and men are together.
To solve this problem, we can use the concept of permutation.
Solution:
Step 1: Find the number of ways to arrange the boys, girls, and men separately.
- The 2 boys can be arranged in 2! ways.
- The 2 girls can be arranged in 2! ways.
- The 2 men can be arranged in 2! ways.
Step 2: Find the number of ways to arrange the groups of boys, girls, and men.
- Since the boys, girls, and men need to be together, we can treat each group as a single entity.
- Therefore, there are 3 entities to arrange: the group of boys, the group of girls, and the group of men.
- These 3 entities can be arranged in 3! ways.
Step 3: Find the total number of ways to arrange the queue.
- Multiply the results from Step 1 and Step 2 to get the total number of ways.
- Total number of ways = 2! x 2! x 2! x 3! = 48
Therefore, the total number of ways to arrange the queue is 48, which is option (B).
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Community Answer
In a ration shop queue 2 boys, 2 girls, and 2 men are standing in such...
Let us assume
A = 2 boys
B = 2 girls
C = 2 men
total number of ways to arranging (A,B,C) =3!
i.e. 3×2×1 = 6,
total ways to arrange
A = 2!
B = 2!
C= 2!
therefore total number of ways to arrange the queue is
6×2×2×2 = 48 (OPTION 'B')
A = 2 boys
B = 2 girls
C = 2 men
total number of ways to arranging (A,B,C) =3!
i.e. 3×2×1 = 6,
total ways to arrange
A = 2!
B = 2!
C= 2!
therefore total number of ways to arrange the queue is
6×2×2×2 = 48 (OPTION 'B')
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In a ration shop queue 2 boys, 2 girls, and 2 men are standing in such a way that the boys the girls and the men are together each.The total number of ways of arranging the queue is _______.a)42b)48c)24d)NoneCorrect answer is option 'B'. Can you explain this answer?
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